The figure here shows a plot of potential energy U versus position x of a 0.878 kg particle that can travel only along an x axis. (Nonconservative forces are not involved.) Three values are U-15.0J, U₂-35.0 J and U-45.0 J. The particle is released atx -4.50 m with an initial speed of 7.99 m/s, headed in the negative x direction. (a) If the particle can reach x -1.00 m, what is its speed there, and if it cannot, what is its turning point? What are the (b) magnitude and (c) direction of the force on the particle as it begins to move to the left of x-4.00 m? Suppose, instead, the particle is headed in the positive x direction when it is released at x - 4.50 m at speed 7.99 m/s. (d) If the particle can reach x - 7.00 m, what is its speed there, and if it cannot, what is its turning point? What are the (e) magnitude and (f) direction of the force on the particle as it begins to move to the right of x-5.00 m? Uct (0)2 UA O 4 x (m) 1 6

University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter8: Potential Energy And Conservation Of Energy
Section: Chapter Questions
Problem 50P: A particle of mass 0.50 kg moves along the x -axis with a potential energy whose dependence on x is...
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The figure here shows a plot of potential energy U versus position x of a 0.878 kg particle that can travel only along an x axis.
(Nonconservative forces are not involved.) Three values are UA-15.0J, U₂ - 35.0J and U-45.0 J. The particle is released atx
-4.50 m with an initial speed of 7.99 m/s, headed in the negative x direction. (a) If the particle can reach x - 1.00 m, what is its speed
there, and if it cannot, what is its turning point? What are the (b) magnitude and (c) direction of the force on the particle as it begins to
move to the left of x-4.00 m? Suppose, instead, the particle is headed in the positive x direction when it is released at x -4.50 m at
speed 7.99 m/s. (d) If the particle can reach x - 7.00 m, what is its speed there, and if it cannot, what is its turning point? What are the
(e) magnitude and (f) direction of the force on the particle as it begins to move to the right of x-5.00 m?
U(J)
Uc
UB
UA
2
4
x (m)
6
Transcribed Image Text:The figure here shows a plot of potential energy U versus position x of a 0.878 kg particle that can travel only along an x axis. (Nonconservative forces are not involved.) Three values are UA-15.0J, U₂ - 35.0J and U-45.0 J. The particle is released atx -4.50 m with an initial speed of 7.99 m/s, headed in the negative x direction. (a) If the particle can reach x - 1.00 m, what is its speed there, and if it cannot, what is its turning point? What are the (b) magnitude and (c) direction of the force on the particle as it begins to move to the left of x-4.00 m? Suppose, instead, the particle is headed in the positive x direction when it is released at x -4.50 m at speed 7.99 m/s. (d) If the particle can reach x - 7.00 m, what is its speed there, and if it cannot, what is its turning point? What are the (e) magnitude and (f) direction of the force on the particle as it begins to move to the right of x-5.00 m? U(J) Uc UB UA 2 4 x (m) 6
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