The figure (Figure 1) shows a model of a crane that may be mounted on a truck.A rigid uniform horizontal bar of mass m1 = 100 kg and length L = 5.70 m is supported by two vertical massless strings. String A is attached at a distance d = 1.40 m from the left end of the bar and is connected to the top plate. String B is attached to the left end of the bar and is connected to the floor. An object of mass m2 = 2500 kg is supported by the crane at a distance x = 5.50 m from the left end of the bar. Throughout this problem, positive torque is counterclockwise and use 9.80 m/s2 for the magnitude of the acceleration due to gravity. Part A Find TA, the tension in string A. Part B Find TB, the magnitude of the tension in string B.

The experiment you did in lab is repeated, using a uniform metal bar that is 80.0 cm long instead of the meterstick. Since the bar is uniform, its center of gravity is at its center. The new experiment uses different hooks for hanging the masses from the bar, with mhook 5.0 g. As in the experiment you did in lab, X1 = 5.00 cm, m1 300.0 g, and Xp = 25.0 cm. In the 1 new experiment, you make the same measurements as in your lab and plot x versus The line that is the best fit to your data has slope 3800 cm · g. What is the mass of m2 + mhook the bar?

The figure (Figure 1) shows a model of a crane that may be mounted on a truck. A rigid uniform horizontal bar of mass m₁ = 100 kg and length L = 5.40 m is supported by two vertical massless strings. String A is attached at a distance d = 2.00 m from the left end of the bar and is connected to the top plate. String B is attached to the left end of the bar and is connected to the floor. An object of mass m2 = 3500 kg is supported by the crane at a distance = 5.20 m from the left end of the bar. Throughout this problem, positive torque is counterclockwise and use 9.80 m/s² for the magnitude of the acceleration due to gravity. Figure B String A m/ 1 of 1 m₂ Part A Find TA, the tension in string A. Express your answer in newtons using three significant figures. ►View Available Hint(s) TA = Submit Part B X Incorrect; Try Again Your answer has dimensions of torque, not force. 17 ΑΣΦ TB = Previous Answers Submit Find TB, the magnitude of the tension in string B. Express your answer in newtons…

The figure (Figure 1) shows a model of a crane that may be mounted on a truck.A rigid uniform horizontal bar of mass m₁ = 95.0 kg and length L = 5.50 m is supported by two vertical massless strings. String A is attached at a distance d = 2.00 m from the left end of the bar and is connected to the top plate. String B is attached to the left end of the bar and is connected to the floor. An object of mass m₂ = 3500 kg is supported by the crane at a distance x = 5.30 m from the left end of the bar. Throughout this problem, positive torque is counterclockwise and use 9.80 m/s² for the magnitude of the acceleration due to gravity. Figure Part A String B String A x m2 mj L Find TA, the tension in string A. Express your answer in newtons using three significant figures. ▸ View Available Hint(s) TA = 9.22x104 N Submit Previous Answers Part B Correct Find TB, the magnitude of the tension in string B. Express your answer in newtons using three significant figures. ▸ View Available Hint(s) ΜΕ ΑΣΦ…

A 1.0 m long uniform iron bar is balanced on triangular support at its middle with 200 g hanging form it on a string tied 10 cm from the middle and mass m hanging form it on a string tied 40 cm from the middle of the bar.  What is the mass m?  cc  (The triangular support and 200 g mass on a string and mass m on a string are the only things touching the bar.)

A uniform beam of length L = 11.7 meters and mass of 109.3 kg is pinned at one end and is being supported by a wire as shown. The wire is connected to the beam x = 3.3 meters from the pin. A person of mass 81.6 kg is standing all the way out on the edge of the beam. If θ = 17.3 degrees and φ = 79.4 degrees, what is the tension in the wire?

In the figure, a nonuniform bar is suspended at rest in a horizontal position by two massless cords as shown in the figure here. One cord makes the angle 0 = 29.5° with the vertical; the other makes the angle p = 60.5° with the vertical. If the length L of the bar is 6.8 m, compute the distance x from the left end of the bar to its center of mass. com X = i