The figure below shows three regions in space separated by two infinite sheets of charge with surface charge densities σ and -σ. Find the magnitude and direction of the electric field in each region in terms of σ and ε. Given σ = 5 x10-6 C/m², find the acceleration vector components of an electron placed in Region 2.

The figure below shows a small, charged bead, with a charge of q = +41.0 nC, that moves a distance of d = 0.174 m from point A to point B in the presence of a uniform electric field  E  of magnitude 255 N/C, pointing right. A positive point charge q is initially at point A, then moves a distance d to the right to point B. Electric field vector E points to the right. (a) What is the magnitude (in N) and direction of the electric force on the bead? magnitude Ndirection     (b) What is the work (in J) done on the bead by the electric force as it moves from A to B?  J (c) What is the change of the electric potential energy (in J) as the bead moves from A to B? (The system consists of the bead and all its surroundings.) PEB − PEA =  J (d) What is the potential difference (in V) between A and B? VB − VA =  V

In Figure (a) below, a particle of charge +Q produces an electric field of magnitude Epart at point P, at distance R from the particle. In Figure (b), that same amount of charge is spread uniformly along a circular arc that has radius R and subtends an angle 8. The charge on the arc produces an electric field of magnitude Earc at its center of curvature P. For what value of 0 (in º) does Earc = 0.75Epart? (Hint: You will probably resort to a graphical solution.) +Q |▬▬▬R—-|| Number i P (a) AR +Q}/0/2/ (b) Units ° (degree:

Given the two charged particles shown in the figure below, find the electric field at the origin. (Let q₁ = -30.00 nC and 92 = 9.00 nC. Express your answer in vector form.) N/C E = -4 92 -2 y (cm) 4 2 -2 -4 2 4 91 x (cm)