The figure below shows all six possible banding patterns for a marker with three alleles in the population. If a mother and father have banding patterns A and C, respectively, which patterns could possibly be in their biological children? Choose all that are correct. A B C D E I F

The figure below shows all six possible banding patterns for a marker with three alleles in the population. If a mother and father have banding patterns A and C, respectively, which patterns could possibly be in their biological children? Choose all that are correct. A B C D E I F

Name: The figure below shows all six possible banding patterns for a marker
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Description: The figure below shows all six possible banding patterns for a marker with three alleles in thepopulation.If a mother and father have banding patterns A and C, respectively, which patterns could possiblybe in their biological children? Choose all th

BIOLOGY:CONCEPTS+APPL.(LOOSELEAF)

10th Edition

ISBN:9781305967359

Author:STARR

Publisher:STARR

Chapter13: Patterns In Inherited Traits

Section: Chapter Questions

Problem 6GP: In sweet pea plant, an allele for purple flowers (P) is dominant when paired with a recessive allele...

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Here's the cheat-sheet below. tt nontaster (homozygous recessive): single band at 221bp TT taster (homozygous dominant): two bands (177bp and 44bp) Tt taster (heterozygous): 3 bands representing both alleles (221bp, 177bp, 44 bp) MARKER tt nontaster TT taster U D Tt taster U D MARKER PBR322/ U D 100 bp ladder BstNI 1857 bp 929 bp 383 bp 121 bp 221 bp 177 bp 44 bp primer dimer if present) This figure shows you expected results for the 3 possible genotypes. The U is for "undigested', meaning what you see before using the restriction enzyme. The D is for digested. Q8) In the figure above, which was the BETTER ladder to use for this experiment? PBR322/BstNI or the 100 bp ladder?
The following alleles exist in combs of chickens: Comb Shape Description Genotype Single Comb homozygous for both r and p rrpp Walnut comb both dominant alleles are present; R and P alleles are present R_P_ Pea comb the dominant allele P is present and the dominant allele R is absent rrP_ Rose comb the dominant allele R is present and the dominant allele P is absent R_pp Which of the following represents the correct phenotypes of the F2 offspring? Phenotype Single Walnut Pea Rose 3/16 9/16 1/16 3/16 b. Phenotype Single Walnut Pea Rose 1/16 9/16 3/16 3/16 c. Phenotype Single Walnut Pea Rose 3/16 1/16 9/16 3/16 d. Phenotype Single Walnut Pea Rose 9/16 3/16 3/16 1/16
Heterozygous Cc chickens express a condition called creeper, in which the leg and wing bones are shorter than normal (cc). The dominant C allele is lethal when homozygous. Skin color is determined by the alleles W and w. W_ chickens have white skin and ww chickens have yellow skin. In a mating between 2 chickens heterozygous for both of these genes: 1) What phenotypes will be observed in the progeny? 2) What fraction of the offspring will have each phenotype? Assign alleles. List possible phentoypes. Make gametes, draw Punnett square, and list fractions of genotypes and/or phenotypes of offspring,
The Andalusian fowl exhibits codominance. The genotypes and phenotypes of Andalusian fowls are shown in the diagram below. White Black Speckled Phenotype White Black Speckled Genotype WW BB BW In a small community south of Seville, the capital city of Spain, speckled hens can be sold for more money at the market then black or white hens. Which of the following rows correctly identifies the cross the farmer should perform to ensure all of his eggs produce speckled offspring AND the phenotypes of offspring produced from crossing a white hen with a speckled rooster? Select one: a. Parental cross to produce Speckled offspring Phenotypes of offspring produced from crossing a white hen and a speckled rooster BB BB White, speckled, and black offspring b. Parental cross to produce Speckled offspring Phenotypes of offspring produced from crossing a white hen and a speckled rooster WW BW White offspring c. Parental cross to produce…
The table below shows the progeny of a test cross of a heterozygote (MmRrDd). Each row shows the number of progeny that inherited each combination of alleles from the heterozygous parent. Which combinations of alleles represent a single crossover? Choose all that apply. Alleles Number mRd Mrd mrd mrD MRD MRd mRD MrD mRD m Rd mrD OMRd Mrd mrd MRD MrD 8 110 38 29 42 31 107 6
In chickens, comb shape is determined by alleles at two loci (R, r and P,p). A walnut comb is produced when at least one dominant allele R ispresent at one locus and at least one dominant allele P is present at asecond locus (genotype R_ P_). A rose comb is produced when at leastone dominant allele is present at the first locus and two recessive allelesare present at the second locus (genotype R_ pp). A pea comb isproduced when two recessive alleles are present at the first locus and atleast one dominant allele is present at the second (genotype rr P_). Iftwo recessive alleles are present at the first and at the second locus (rrpp), a single comb is produced. Progeny with what types of combs andin what proportions will result from the following crosses? a. RR PP × rr pp b. Rr Pp × rr pp c. Rr Pp × Rr Pp d. Rr pp × Rr pp e. Rr pp × rr Pp f. Rr pp × rr pp
Phenotype Genotype Wide bands BB medium Bands Bb narrow bands bb Phenotype Genotype Complete Washing WW half washing Ww No washing ww If a raccoon with a wide tail band that washes only some of its food is crossed with a raccoon with a narrow tail band that doesn’t wash any food, what percentage of their offspring would be medium-tailed and washes all its food? Show COMPLETE cross.
The gel image below shows 7 alleles, let's call them 1-7 in order of size, with 1 being the largest and 7 being the smallest. In this sample of 11 individuals, what percentage of individuals have allele 7? Please type your answer as a number, rounded to the nearest whole percentage, just type the number, not the symbol. Answer: In the gel image below 0 percent of individuals have allele 7. Photograph of UV illuminated 1% agarose TBE gel run for 40 minutes at 120 V, showing the result of PCR from a variable number tandem repeat region in 11 different individuals (A-K) ... A B C DE F G H IJK 2000| 1650 1000 850 600 500 Кey: Lane 1: DNA ladder, see image for fragment sizes (bp). Lanes 2-13: PCR products from the same variable number tandem repeat (VNTR) autosomal region of DNA from 11 different individuals (A-K).
The fur color gene in rabbits has a dominant allele B with a black phenotype and a recessive allele with a brown phenotype. The rabbit hair length gene has a dominant allele S for short hair, and a long hair recessive allele s. In a cross between a homozygous black-long-hair rabbit with a homozygous brown-short rabbit, what would be the genotype(s) B_s_ v and phenotype(s) [ Select ] of the F1 generation? What would be the genotype(s) [ Select ] and phenotype(s) [ Select ] of the F2 generation?
What type of allele dominance is expressed in each of the Punnet Squares shown. Complete dominance, Incomplete dominance, Codominance. bOb R R B Rr Rr Bb Bb w RW RW B Rr Rr ww Bb Bb W TOTO RW RW select Incomplete dominance select select Complete dominance Codominance B b B BB BB B BB Bb CACA CACC W BW BW b Bb bb select select CAC CUCU I ved 2 pink white select
In chickens, comb shape is determined by genes at two loci (R, r and P, p). A walnut comb is produced when at least one dominant gene R is present at one locus and at least one dominant gene P is present at a second locus (genotype R_ P_). A rose comb is produced when at least one dominant gene is present at the first locus and two recessive genes are present at the second locus (genotype R_ pp). A pea comb is produced when two recessive genes are present at the first locus and at least one dominant gene is present at the second (genotype rr P_). If two recessive genes are present at the first and the second locus (rr pp), a single comb is produced. Give genotypes for comb shape of the parents in the following cross: Rose crossed with pea produces 20 walnut offspring. O A. Rr pp x Rr Pp B. Rr pp x rr PP C. Rr pp x rr Pp D. RR pp x rr PP O E. RR pp x rr Pp Reset Selection Mark for Douiouu
The result of a test cross of a yeast cell that is heterozygous for three genes are summarized in the table (below), which shows the number of offspring that inherited each combination of alleles from the heterozygous parent. Use the data collected to make a genetic map of the three genes L, Q, and D. 。 D-Q: 。 D-L: I 。 Q-L: I I L I L L q Alleles cM Q d cM q cM Q q q D D D L Q d d d 104 27 78 Report your results by entering the genetic distance between each pair of genes in the blanks below. Round to the nearest 0.1 CM. 64 28 62 106 81