**Problem Statement:**The figure below shows a uniform electric field of magnitude $ E = 480 \, \text{N/C} $ making an angle of $ \phi = 66.5^\circ $ with a flat surface of area $ A = 3.10 \, \text{m}^2 $. What is the magnitude of the electric flux through this surface (in $ \text{N} \cdot \text{m}^2/\text{C} $)?**Diagram Explanation:**- The diagram depicts a flat rectangular surface with lines representing a uniform electric field, denoted as $ \vec{E} $.- The electric field lines intersect the surface at an angle, $ \phi = 66.5^\circ $, from the normal (perpendicular) to the surface.- The angle is clearly marked between the normal to the surface and the direction of the electric field $ \vec{E} $.To calculate the electric flux ($ \Phi $), use the formula:\[\Phi = E \cdot A \cdot \cos(\phi)\]where- $ E = 480 \, \text{N/C} $- $ A = 3.10 \, \text{m}^2 $- $ \phi = 66.5^\circ $

The electric flux () through a surface is given by the formula:where: is the magnitude of the…

Answered: The figure below shows a uniform…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Related questions

Concept explainers

Question

100%

**Problem Statement:**

The figure below shows a uniform electric field of magnitude $ E = 480 \, \text{N/C} $ making an angle of $ \phi = 66.5^\circ $ with a flat surface of area $ A = 3.10 \, \text{m}^2 $. What is the magnitude of the electric flux through this surface (in $ \text{N} \cdot \text{m}^2/\text{C} $)?

**Diagram Explanation:**

- The diagram depicts a flat rectangular surface with lines representing a uniform electric field, denoted as $ \vec{E} $.
- The electric field lines intersect the surface at an angle, $ \phi = 66.5^\circ $, from the normal (perpendicular) to the surface.
- The angle is clearly marked between the normal to the surface and the direction of the electric field $ \vec{E} $.

To calculate the electric flux ($ \Phi $), use the formula:

\[
\Phi = E \cdot A \cdot \cos(\phi)
\]

where
- $ E = 480 \, \text{N/C} $
- $ A = 3.10 \, \text{m}^2 $
- $ \phi = 66.5^\circ $

Expert Solution

Step 1: Formula for electric flux through a surface

The electric flux ( $straight capital phi subscript E$ ) through a surface is given by the formula:

$straight capital phi subscript E equals E times A times cos invisible function application not stretchy left parenthesis theta not stretchy right parenthesis$

where:
$E$ is the magnitude of the electric field,
$A$ is the area of the surface, and
$theta$ is the angle between the electric field and the normal to the surface.

Step by step

Solved in 3 steps with 12 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions