College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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- Two metal spheres of identical mass m = 4.60 g are suspended by light strings 0.500 m in length. The left-hand sphere carries a charge of 0.765 µC, and the right-hand sphere carries a charge of 1.47 μC. What is the equilibrium separation between the centers of the two spheres? 0.6078 x Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four- digit accuracy to minimize roundoff error. marrow_forwardThe gecko is sticking upside down to a smooth ceiling. The remarkable adhesion might be due to static electricity. Gecko feet are covered with microscopic hairs. When these hairs rub against a surface, charges separate, with the hair developing a positive charge and negative charge forming below the surface. There is an attractive force between the separated charges. This is an effective means of adhering to a surface, but it comes at a cost: Two planes of charge are like two charged plates of a capacitor, which takes energy to charge. Doubling the amount of charge on each surface increases the attractive force, but also increases the energy required to separate the charge. Part A By what factor does this energy increase? (UElec){ (UElec); ΕΧΕΙ ΑΣΦ Submit Request Answer Provide Feedback ?arrow_forwardThe figure below shows three small, positively charged spheres at three corners of a rectangle. The particle at upper left has a charge q, = 8.00 nC, the one at the lower left has a charge of q2 = 4.00 nC, and the one at lower right has a charge q, = 6.00 nC. The rectangle's horizontal side has length x = 5.50 cm and its vertical side has length y = 4.00 cm. (a) What is the electric potential (in V) at the upper-right corner of the rectangle? (Assume the zero of electric potential is at infinity.) 2.65*10**3 What is the electric potential at a point due to a single charged particle? Given more than one charged particle, how do you find the total potential at a point? How far is each charge from upper right point? Be careful with units and signs. V (b) What would be the potential (in V) at the upper-right corner if the charge q, at lower left was -4.00 nC instead? 2.71*10**3 Use the same method as used in part (a). Note q, is now the opposite sign. How does this affect the potential due…arrow_forward
- Three charged marbles are glued to a nonconducting surface and are placed in the diagram as shown. The charges of each marble are q1 = 6.20 µC, q2 = 1.43 µC, and q3 = −2.01 µC. Marble q1 is a distance r1 = 3.00 cm to the left of the marble q2, while marble q3 is a distance r3 = 2.00 cm to the right of the marble q2. Calculate the magnitude of the electric field a distance r' = 1.00 cm to the left of the center marble.N/C Another marble is placed 1 cm to the left of the middle marble. If this new marble has a charge of 3.62 µC, calculate the magnitude and direction of the force on it.arrow_forwardConsider three identical metal spheres, A, B, and C. Sphere A carries a charge of +6q. Sphere B carries a charge of -5g. Sphere C carries no net charge. Spheres A and B are touched together and then separated. Sphere C is then touched to sphere A and separated from it. Last, sphere C is touched to sphere B and separated from it. For the following questions, express your answers in terms of q. (a) How much charge ends up on sphere C? 0.5 (b) What is the total charge on the three spheres before they are allowed to touch each other? 0.25 (c) What is the total charge on the three spheres after they have touched? 0.375 Additional Materials M eBook JAN 12 tv MacBook Air DII 80 F7 F8 F6 esc F4 F5 F1 F2 F3 * 24 %arrow_forward= 32.2 nC. The figure below shows a small, hollow, plastic sphere hanging vertically from a thin, lightweight thread. The sphere has a mass of 7.10 g and a uniformly distributed charge of 91 Directly below it is a second sphere with the same mass, but a charge of 92 = -58.0 nC. (Assume this second sphere is fixed in place.) The centers of the two plastic spheres are a distance d = 2.00 cm apart. 91 92 (a) What is the tension (in N) in the thread? 0.11154376 N (b) The thread will break if the tension in it exceeds 0.180 N. What is the smallest possible value of d (in cm) before the thread breaks? The analysis is the same as in part (a), including the magnitude and direction of the gravitational and electric forces. Note that Coulomb's law depends on the square of the distance d. Use the threshold value of the tension to solve for d. cmarrow_forward
- The figure below shows two identical small, charged spheres. One of mass 4.3 g is hanging by an insulating thread of length 20.0 cm. The other is held in place and has charge q₁ = -3 -3.1 μC. The thread makes an angle of 18° with the vertical, resulting in the spheres being aligned horizontally, a distance r apart. Determine the charge 92 on the hanging sphere. nC 20.0 cm 18⁰ 91 92 ✈arrow_forwardThree charged marbles are glued to a nonconducting surface and are placed in the diagram as shown. The charges of each marble are q = 6.30 µC, 92 = 1.93 pC, and 93 = -2.20 pC. Marble q, is a distance r = 3.00 cm to the left of the marble q2, while marble q3 is a distance r3 = 2.00 cm to the right of the marble q2, as shown. Calculate the magnitude of the electric field a distancer = 1.00 cm to the left of the center marble. N/C observation point Another marble is placed 1 cm to the left of the middle marble. If this new marble has a charge of -3.60 pC, calculate magnitude and direction of the force on it. magnitude direction -Select varrow_forwardThe figure below shows a small, hollow, plastic ball hanging vertically from a thin, lightweight string. The ball has a mass of 6.30 g and a uniformly distributed charge of q₁ = 30.7 nC. Directly below it is a second ball with the same mass, but a charge of 92 -58.0 nC. (Assume this second ball is fixed in place.) The centers of the two plastic balls are a distance d = 2.00 cm apart. = 91 + 92 (a) What is the tension (in N) in the string? .10174 N Need Help? (b) The string will break if the tension in it exceeds 0.180 N. What is the smallest possible value of d (in cm) before the string breaks? 0.0339 The analysis is the same as in part (a), including the magnitude and direction of the gravitational and electric forces. Note that Coulomb's law depends on the square of the distance d. Use the threshold value of the tension to solve for d. cm Read Itarrow_forward
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