The figure below gives versus the sine of the angle in a double-slit interference experiment using light of wavelength 538. nm. What is the slit separation (in um)? ß (rad) 30.0 20.0 10.0 0.5 1 sino

You measure three segments of the distance between a diffraction slit an the screen on which the pattern forms: x1 = (15.8 ± 0.2) cm, x2 = (6.7 ± 0.1) cm, and x3 = (11.3 ± 0.1). What is the uncertainty of the total distance x1 + x2 + x3? Group of answer choices 0.4 cm 0.5 cm 0.2 cm 0.3 cm 0.1 cm

Chapter 36, Problem 009 A slit 0.803 mm wide is illuminated by light of wavelength 481 nm. We see a diffraction pattern on a screen 3.68 m away. What is the distance in millimeters between the first two diffraction minima on the same side of the central diffraction maximum? Number Units Use correct number of significant digits; the tolerance is +/-2%

The figure below shows a radio wave transmitter and a receiver separated by a distance d = 50distance d = 50, 0 m, both being at a height h = 35, 0 m above the ground. The receiver canThe receiver can receive signals either directly or indirectly from reflected signals on the ground. Suppose that theground is leveled and a 180o phase shift occurs in the reflection.Determine the longest wavelengths that interferea. constructively;b. destructively.

0 The following questions refer to the following pattern obtained from a double-slit interference experiment. E is the center of the pattern. A B CD E F G H Fringe is a first order maximum. MAY SHIZA 2 a. G Ob. H OC. F Od. 1 ů QUESTION 5 281 O 5 tv

In a Young's double slit experiment the wavelength of light is ?λ, separation between the slits is ?a and the distance to the screen is ?D. Give an expression for the interference fringe width ?w on screen if ?≫?D≫a. For Greek letters such as ?λ use the text equivalent - e.g. "lambda" (without the quotes, e.f. for ??Dλ use D*lambda).