++ The figure above shows a cross section of a very long, hollow dielectric (insulating) tube (the outer, lighter colored region with + signs) with charge distributed uniformly throughout the tube walls. The volume charge density in the tube wall is p. This tube has inner radius a, and outer radius b, and length L that is much greater than b. The region inside the tube (r b) are empty. (The reason it is important that the tube is made of an insulator is that we can have charge distributed throughout its material; As we have discussed (or will soon,) all the excess charge on a conductor ends up at the surfaces of the conductor. Using Gauss's law, find the magnitude of the electric field at any point inside the tube wall (a b, the field should be the same as that of a long line of uniform charge whose charge per unit length is given by the charge density p multiplied by the cross sectional area of the tube wall. Does your expression derived in step (c) correctly model this behavior?
++ The figure above shows a cross section of a very long, hollow dielectric (insulating) tube (the outer, lighter colored region with + signs) with charge distributed uniformly throughout the tube walls. The volume charge density in the tube wall is p. This tube has inner radius a, and outer radius b, and length L that is much greater than b. The region inside the tube (r b) are empty. (The reason it is important that the tube is made of an insulator is that we can have charge distributed throughout its material; As we have discussed (or will soon,) all the excess charge on a conductor ends up at the surfaces of the conductor. Using Gauss's law, find the magnitude of the electric field at any point inside the tube wall (a b, the field should be the same as that of a long line of uniform charge whose charge per unit length is given by the charge density p multiplied by the cross sectional area of the tube wall. Does your expression derived in step (c) correctly model this behavior?
Related questions
Question
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 2 images