The evolution of a star depends on its size. If a star is sufficiently large, the gravity forces holding it together may be large enough to collapse it into a very dense object composed mostly of neutrons. The density of such a neutron star is about 1014 times that of the Earth. Suppose that a star initially had a radius of 7 x 108 km, and it rotated once every 26 days. What would be the period of rotation if the star collapsed to a radius of 15 km? (1.19 x 10-14 days)

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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The evolution of a star depends on its size. If a star is sufficiently large, the gravity
forces holding it together may be large enough to collapse it into a very dense object
composed mostly of neutrons. The density of such a neutron star is about 1014 times
that of the Earth. Suppose that a star initially had a radius of 7 x 108 km, and it
rotated once every 26 days. What would be the period of rotation if the star collapsed
to a radius of 15 km? (1.19 x 10-14 days)
Transcribed Image Text:The evolution of a star depends on its size. If a star is sufficiently large, the gravity forces holding it together may be large enough to collapse it into a very dense object composed mostly of neutrons. The density of such a neutron star is about 1014 times that of the Earth. Suppose that a star initially had a radius of 7 x 108 km, and it rotated once every 26 days. What would be the period of rotation if the star collapsed to a radius of 15 km? (1.19 x 10-14 days)
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