The equilibrium equation of force in horizontal direction is, Та cos 30°- Tв сos 45° (IV) TA = 0.81657; • Ta is the tension in cord A • Tg is the tension in cord B The equilibrium equation of force in vertical direction is, TA sin 30° + Tc = TB sin 45° (V) Ta is the tension in cord A • TB is the tension in cord B • Tc is the tension in cord C The equilibrium equation of force for suspended object is, Tc = w (VI) • Tc is the tension in cord C • w is weight of suspended object Conclusion: Substitute 0.8165TB for TA and w for Te in eqs. (V) to find Tg. (0.8165TB) sin 30° + w = Tg sin 45° 0.299TB = w Тв — 3.346w Substitute 3.346w for Tg in eqs. (IV) to find TĄ. TA = 0.8165 x (3.346w) TA = 2.732w Therefore tension in cord A is 2.732w. Tension in cord B is 3.346w. Tension in cord C is w.

The equilibrium equation of force in horizontal direction is, Та cos 30°- Tв сos 45° (IV) TA = 0.81657; • Ta is the tension in cord A • Tg is the tension in cord B The equilibrium equation of force in vertical direction is, TA sin 30° + Tc = TB sin 45° (V) Ta is the tension in cord A • TB is the tension in cord B • Tc is the tension in cord C The equilibrium equation of force for suspended object is, Tc = w (VI) • Tc is the tension in cord C • w is weight of suspended object Conclusion: Substitute 0.8165TB for TA and w for Te in eqs. (V) to find Tg. (0.8165TB) sin 30° + w = Tg sin 45° 0.299TB = w Тв — 3.346w Substitute 3.346w for Tg in eqs. (IV) to find TĄ. TA = 0.8165 x (3.346w) TA = 2.732w Therefore tension in cord A is 2.732w. Tension in cord B is 3.346w. Tension in cord C is w.

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter1: Physics And Measurement

Section: Chapter Questions

Problem 1.67AP: A rod extending between x = 0 and x = 14.0 cm has uniform cross-sectional area A = 9.00 cm2. Its...

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