The equilibrium constant, Ko, for the following reaction is 7.00×10-5 at 673 K. NH4I(s) =NH3(g) + HI(g) Calculate the equilibrium concentration of HI when 0.319 moles of NH4I(s) are introduced into a 1.00 L vessel at 673 K. [HI] = M

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Q: The equilibrium constant, Kc, for the following reaction is 1.20×10-2 at 500 K. PCl5(g) PCl3(g) +…

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Q: The equilibrium constant, K. for the following reaction is 55.6 at 698 K. H2 (g) + 12 (g)=2 HI (g)…

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Q: -5 The equilibrium constant, Kc, for the following reaction is 7.00 x 10 at 673 K. NH₂I(8) NH3 (g) +…

A: moles of NH4I = 0.599 molvolume of vessel = 1.00 LT = 673 KKc = 7.0010-5

Q: The equilibrium constant, Kc, for the following reaction is 9.52×10-2 at 350 K. CH4 (g) + CCl4 (g) 2…

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Q: The equilibrium constant, Kc, for the following reaction is 1.80x10-2 at 698K. 2HI(g)H2(g) + I2(g)…

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Q: Suppose a 500, mil. flask is filled with 1.8 mol of OCI, 1.0 mol of BrOCI and 1.4 mol of BrCl. The…

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Q: The equilibrium constant, Ke, for the following reaction is 0.0129 at 600 K. COC12 (g) CO(g) +…

A: we have to calculate the concentration of COCl2 at equilibrium

Q: A sample of 0.750 mol of PCl5 is heated to 250oC in a 1.00 L reaction container to produce PCl3 and…

A: [PCl3] = 0.0177 M[Cl2] = 0.0177 MExplanation:

Q: The equilibrium constant, Ke, for the following reaction is 0.0180 at 698 K. 2HI(g) → H₂(g) + 1₂ (9)…

A: Given, 2HI(g) ⇌ H2(g) + I2(g) Equilibrium constant (KC) = 0.0180  Temperature = 698 K Initially…

Q: A student ran the following reaction in the laboratory at 529 K: COC12 (9)CO(g) + Cl₂ (9) When she…

A: The equilibrium constant of a reaction is defined as the ratio of the concentration of products to…

Q: The equilibrium constant, K, for the following reaction is 10.5 at 350K. 2CH,Cl2(g) =CH4(g) +…

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Q: The equilibrium constant, Ke, for this reaction is 57. H2 (9) + I2(9) = 2HI(9) If the equilibrium…

A: Here the equilibrium constant is 57 for the reaction  H2 + I2 < => 2HI . The equilibrium…

Q: The equilibrium constant Kc for the gaseous reaction HCHO(g) ⇀↽ H2(g) + CO(g) has the numerical…

A: Equilibrium point is the point where rate of forward reaction is equal to the rate of backward…

Q: The equilibrium constant, K, for the following reaction is 1.20×10-2 at 500 K. PCI5(g) PCI3(g) +…

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Q: A student ran the following reaction in the laboratory at 284 K: 2NO(g) + Br2(g) = 2NOBr(g) When she…

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Q: The equilibrium constant K, for the equation 2H2(g) + CO(g)=CH;OH(g) is 35 at a certain temperature.…

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Q: student ran the following reaction in the laboratory at 292 K: 2CH2Cl2(g) CH4(g) + CCl4(g) When…

A: The question is based on the principle equilibrium. we have been given equilibrium concentration of…

Q: A student ran the following reaction in the laboratory at 244 K: 2NOBr(g) ⇒ 2NO(g) + Br₂ (9) When…

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Q: The equilibrium constant, Kc, for the following reaction is 7.00×10-5 at 673 K.NH4I(s) NH3(g) +…

A: Equilibrium constant (Kc) defines a state when no more change in the concentration of reactants or…

Q: The equilibrium constant, K, for the following reaction is 9.23x10-3 at 304 K. NH4HS(s) NH3(g) +…

A:

Q: The equilibrium constant, K, for the following reaction is 1.80x104 at 298 K. NH,HS(s)=NH3(g)+…

A: Assuming y moles of NH4HS reacted as per the above reaction Hence we can say that moles of H2S and…

Q: A student ran the following reaction in the laboratory at 565 K: Co(g) + Cl2(g) = cocl2(g) When she…

A: Recall the given reaction :     CO (g) +  Cl2 (g)  <------>  COCl2 (g)  The equilibrium…

Q: A student ran the following reaction in the laboratory at 545 K: COC12 (g) CO(g) + Cl₂ (g) When she…

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Q: A student ran the following reaction in the laboratory at 1083 K: 2S03(g)2s02(9) + 02(9) When she…

A: Equilibrium constant is defined as ratio of equilibrium molar concentration of product raised to…

Q: The equilibrium constant, K., for the following reaction is 1.29×10-2 at 600 K. COCL,(g)CO(g) +…

A: Given equilibrium is  COCl2(g) <---> CO(g) + Cl2(g)  Equilibrium constant, Kc = 1.29×10-2…

Q: The equilibrium constant, Ke, for the following reaction is 83.3 at 500 K. PCI,(g) + Cly(g)=PCI,(g)…

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Q: The equilibrium constant, Ke, for the following reaction is 1.80×10-2 at 698 K. 2HI(g)H2(g) + I(g)…

A: The equilibrium reaction taking place is given as, => 2 HI (g) --------> H2 (g) + I2 (g)…

Q: The equilibrium constant, K., for the following reaction is 1.29×102 at 600 K. COCI,(2)CO(g) + Cl(g)…

A:

Q: A student ran the following reaction in the laboratory at 286 K: 2CH2Cl2(g) CH4(g) + CCl4(g) When…

A: 2CH2Cl2(g)     =     CH4(g)       +   CCl4(g) Kc = [CH4][CCl4]/[CH2Cl2]2

Q: The equilibrium constant, Kc, for the following reaction is 9.52×10-2 at 350 K. CH4 (g) + CCl4 (g)…

A:

Q: The equilibrium constant, Kc, for the reaction PCl3 (g) + Cl2 (g) PCl5 (g) equals 14 at 800 °C. If…

A: NOTE : The temperature at which the equilibrium concentrations are asked is different from the…

Q: The equilibrium constant, K, for the following reaction is 1.29x10-2 at 600 K. COC,(g) CO(g) +…

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Q: The equilibrium constant, Kc, for the following reaction is 0.0290 at 1150 K. 2SO3(g)2SO2(g) + O2(g)…

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Q: Consider the following equilibrium. Na(g) + O2(g) 2 NO(g) At 2300 K, the equilibrium constant K-1.7…

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Q: The equilibrium constant, Kç, for the following reaction is 10.5 at 350 K. 2CH;Cl½(g)CH4(g) +…

A: It can be solved as:-

Q: The equilibrium constant, Kc, for the following reaction is 0.00650 at 298 K. 2NOBr(g) 2NO(g) + Br₂…

A: The given equation is      2NOBr (s) 2NO (g) + Br2 (g) Kc = 0.00650Volume of container = 15.6 L