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The equation of the tangent line at point P(1,6) is y = help (formulas) Hint: The equation of the line tangent to f(x) at x = a is y = f(a) + m₁an (x - a)

The equation of the tangent line at point P(1,6) is y = help (formulas) Hint: The equation of the line tangent to f(x) at x = a is y = f(a) + m₁an (x - a)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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need help with part 3 if you could break down the steps that would be great thanks

The points P(1,6) and Q(x, y) are on the graph of the function f(x) = x² +5. Complete the table with the values for the slope of the secant line passing through points P and Q. Do not round until the end of your calculations, then round to 4 decimal places. help (numbers) Hint: x 1.1 y f(1.1) Hint: m sec 2.1 1.01 (1.01) 2.01 1.001 f(1.001) 2.001 1.0001 f(1.0001) 2.0001 ▾ Part 2 - 1 point Using the values in the right column of the table, the estimated value of the slope of the line tangent to f at x = 1 is man = 2 help (numbers) Hint: Part 3 - 1 point The equation of the tangent line at point P(1,6) is y = help (formulas) The equation of the line tangent to f(x) at x = a is y = f(a) + m₁an(x − a) -
Transcribed Image Text:The points P(1,6) and Q(x, y) are on the graph of the function f(x) = x² +5. Complete the table with the values for the slope of the secant line passing through points P and Q. Do not round until the end of your calculations, then round to 4 decimal places. help (numbers) Hint: x 1.1 y f(1.1) Hint: m sec 2.1 1.01 (1.01) 2.01 1.001 f(1.001) 2.001 1.0001 f(1.0001) 2.0001 ▾ Part 2 - 1 point Using the values in the right column of the table, the estimated value of the slope of the line tangent to f at x = 1 is man = 2 help (numbers) Hint: Part 3 - 1 point The equation of the tangent line at point P(1,6) is y = help (formulas) The equation of the line tangent to f(x) at x = a is y = f(a) + m₁an(x − a) -
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