The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula: R 12/23 n E=- In this equation R, stands for the Rydberg energy, and n stands for the principal quantum number of the orbital that holds the electron. (You can find the value of the Rydberg energy using the Data button on the ALEKS toolbar.) Calculate the wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron from an orbital with n= 12 to an orbital with n= 11. Round your answer to 3 significant digits. um

The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula: R 12/23 n E=- In this equation R, stands for the Rydberg energy, and n stands for the principal quantum number of the orbital that holds the electron. (You can find the value of the Rydberg energy using the Data button on the ALEKS toolbar.) Calculate the wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron from an orbital with n= 12 to an orbital with n= 11. Round your answer to 3 significant digits. um

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

An aqueous solution of sodium chloride,NaCl , is made by dissolving 1.01 grams of sodium chloride in sufficient water in a 50.0 mL volumetric flask, and then adding enough water to fill the flask to the mark. What is the weight/volume percentage of sodium chloride in the solution? Weight/volume percentage = %
Given the equation 2N₂(g) + O₂(g) ⇒ 2N₂O(g) Kc = 1.2x10-¹2, what is Kc for the equation 4N2O(g) = 4N₂(g) + 20₂(g)? 6.9x1023 2.4x1012 1.2x10-12 Not enough information is provided to calculate Kc'.
NHẠNO3 MgSO4 [1] Mass of salt (g) 1.968 1.981 [2] Volume of DI water (mL) 50.0 50.0 0.039 0.0396 Mass of DI water (g) [3] Temperature of DI water (°C) 22.5 22.5 [4] Temperature of mixture after dissolution (°C) 19.5 27.1 3 4.6 Temperature difference (°C) [5] Total mass in reaction (g) [6] Enthalpy of solution AHsolution (cal/mol)
Please answer question number 1 correctly with the correct answer. there is a picture of an example of a ''Dimensional analysis Format' below. please write out all work showing the math in dimensional analysis format. Question 3: Calculate the molar mass of each of the following ionic Compounds: A. KMnO4 B. Ca3(PO4)2
barrels of toluene are being stored on the moon for use in onsite manufacturing. If each barrel contains 42 gallons, how many moles are in each container? The specific gravity of toluene is 0.867 and its molecular formula is C7H8. you may assume the molecular weights of carbon and hydrogen are 12 and 1 g/mol, respectively.
For the compound (IUPC) CH3 H;C CH3 H3C CH3
Mining companies use this reaction to obtain iron from iron ore: Fe2O3(s)+3CO(g) → 2Fe(s)+3CO2(g)Fe2O3(s)+3CO(g) → 2Fe(s)+3CO2(g) The reaction of 182 gg of Fe2O3Fe2O3 with 85.8 gg of COCO produces 70.6 gg of FeFe. Calculate the theoretical yield of solid iron. Express the mass in grams to three significant figures. SEE PIC.
An acid is dissolved in another acid. Acid i has a specific gravity of 2.46 and a mass of 50 grams. Acid 2 is 50 mL What is the percentage by volume of the solute if Acid i is the solute in the solution? Assume the density of water to be i gram per ml. O 71.0983 O 40.6504 O 100.0000 O 28.9017
4) ½N2(g) + 02(g)= NO2(g) Kc = 1.04 x 10-9 %3D N2(g) + 202(g) =N204(g) br Kc = 7.42 x 10-18 edmi mcilups Calculate Kc for each of the following. (a) 2NO2(g) = N2(g) + 202(g) (b) N2(g) + 202(g) =N2O4(g) t a0002e muinditiops yiwollol srt tol oolav52 s (S 0 at100 Sn ot beonbonni to l o 2elom 021 bns tH to olom 021 H(8) +P(6) SHI) onrr to el lo 2slom 02 Jom 02.1 11 Smuidiliups ie inseng o1s IH lo 2olom vitsm wod (c) 2NO2(g) = N2O4(g)
1a. Determine the volume of 1.000 g of water (Densitywater = 0.9999 g/mL). 1b. Determine the volume of 1.000 g of ice (Density ce = 0.9168 g/cm³). (1 mL = 1 cm³) %3D %3D 1c. From the volumes above, what can we conclude about 1.000 g of water when it freezes?
ᴡʜᴀᴛ ɪꜱ ᴛʜᴇ ᴘᴇʀᴄᴇɴᴛ ᴛʜᴇᴏʀᴇᴛɪᴄᴀʟ ᴀɪʀ ꜰᴏʀ ᴀ ᴄᴏᴍʙᴜꜱᴛɪᴏɴ ᴘʀᴏᴄᴇꜱꜱ ᴛᴏ ᴡʜɪᴄʜ ᴛʜᴇ ꜰᴜᴇʟ ᴀɴᴅ ᴄᴏᴍʙᴜꜱᴛɪᴏɴ ᴏꜰ ɢᴀꜱ ᴀɴᴀʟʏꜱɪꜱ ᴀʀᴇ ᴋɴᴏᴡɴ ᴀꜱ ꜰᴏʟʟᴏᴡꜱ:
Density of an aqueous solution of nitric acid is 1.43 g/mL. If this solutioin contained 36.0% nitric acid by mass, what volume of solution would be needed to supply 1.50 mmol of nitric acid?