The energies in a 2D particle-in-a-box are given by h² Exm, 3m² = (1, ²+1, ²) 2+ n ,n 8mL2 in which the box is a square enclosure with Lx = Ly = L, and nx, ny = 1, 2, 3,.... (a) If the particle is an electron and L = 300 pm (assume three significant figures), find the value of the lowest energy level in units of 10-18 J (that is, if the energy is 5.00 × 10-18 J, you would report it as "5.00").
The energies in a 2D particle-in-a-box are given by h² Exm, 3m² = (1, ²+1, ²) 2+ n ,n 8mL2 in which the box is a square enclosure with Lx = Ly = L, and nx, ny = 1, 2, 3,.... (a) If the particle is an electron and L = 300 pm (assume three significant figures), find the value of the lowest energy level in units of 10-18 J (that is, if the energy is 5.00 × 10-18 J, you would report it as "5.00").
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Transcribed Image Text:The energies in a 2D particle-in-a-box are given by
h²
8mL 2
in which the box is a square enclosure with Lx = Ly = L, and nx, ny = 1, 2, 3,... .
(a) If the particle is an electron and L = 300 pm (assume three significant figures), find the value of the lowest energy
level in units of 10-18 J (that is, if the energy is 5.00 × 10-18 J, you would report it as "5.00").
E
n, n
(n₂ ² + n₂²)
y
x y
Expert Solution
Step 1
Given that- L=300 pm= 300×10^-12 m
Energy in a 2D particle box.
Lx =Ly =L and nx =ny =n
To Calculate- the value of lowest energy level in units of 10^-18 J.
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