The end point in a titration of 50.00 mL of aqueous NaOH was reached by the addition of 35.23 mL of 0.250 M aqueous HCI titrant. Calculate the molarity of the NaOH solution. The titration reaction equation is: NaOH(aq) + HCI (aq) —> NaCl(aq) + H2O(l)

A student prepares a dilute solution of sodium hydroxide, NaOH (aq), starting with 6 M sodium hydroxide. She then titrates a 1.372 g sample of KHP with the dilute sodium hydroxide solution, NaOH (aq), to a phenolphthalein end point.   A.) If the titration required 21.84 mL of sodium hydroxide, NaOH (aq), calculate the molar concentration of the sodium hydroxide solution, NaOH (aq). (Remember that KHP is potassium hydrogen phthalate, KHC8H4O4, NOT potassium hydrogen phosphorus!)   B.) The student uses the same sodium hydroxide to titrate 10.00 mL of vinegar to a phenolphthalein end point. If the titration required 27.48 mL of sodium hydroxide, NaOH (aq), calculate the molar concentration of acetic acid, HC2H3O2 (aq), in the vinegar.   C.) Calculate the mass percent of acetic acid, HC2H3O2 (aq), in the vinegar using the molar concentration for acetic acid, HC2H3O2 (aq), determined in part b and assuming the density of the solution is 1.01 g/mL.

You have a 1.153 g sample of an unknown solid acid, HA, dissolved in enough water to make 20.00 mL of solution. HA reacts with KOH(aq) according to the following balanced chemical equation:HA(aq)+KOH(aq) --------->KA(aq)+H2O(l)       If 14.90 mL of 0.585 M KOH is required to titrate the unknown acid to the equivalence point, what is the concentration of the unknown acid? ______ M      What is the molar mass of HA? _____  g/mol

A 0.200 g sample of an unknown monoprotic acid (e.g., HX) is dissolved in water and titrated with NaOH. The equivalence point of the titration is reached after the addition of 19.03 mL of 0.1750 M NaOH. Calculate the molar mass of the acid. NaOH(aq) + HX(aq) → H₂O(1) + NaX(aq) (Balanced) Reminder - the equivalence point is where stoichiometric amounts of acid and base have been added! 36.56 g/mol (HCI) O20.00 g/mol (HF) O100.46 g/mol (HCIO4) 60.05 g/mol (HCH3COO) 80.91 g/mol (HBr)