The electrons in a particle beam each have a kinetic energy of 1.53x10-17 J. What are the magnitude and direction of the electric field that stops these electrons in a distance of 10.1 cm? 9.47x10² N/C Computer's answer now shown above. Tries 0/6

A uniform electric field exists in the region between two oppositely charged plane parallel plates. An electron is released from rest at the surface of the negatively charged plate and strikes the surface of the opposite plate, 3.40 cm distant from the first, in a time interval of 1.90×10-8 s Part A Part B Find the magnitude of this electric field. Find the speed of the electron when it strikes the second plate. Express your answer in newtons per coulomb. Express your answer in meters per second. να ΑΣφ 5 ? | να ΑΣφ ? E = N/C m/s

Starting from rest, a proton was accelerated by an electric field. After a distance of 1.35 m the proton reaches a speed of 1.97 x 105 m/s (m, = 1.67 x 10-27 kg, q,= 1.60 x 10-19 C). a) What is the final kinetic energy of the proton? b) What is the potential energy difference of the proton? c) What is the magnitude of the electric field?

A. Show on the drawing below the electric field, B. What is the magnitude of electric field between A and B (distance A and B d=0.03m) C. If a charge particle at point A q = 2 x 10-6 C move to point B, calculate the amount of work done by the electric field on the particle in the figure. D. Calculate the amount of force and acceleration of particle 6 V 5 V 4 V 3 V 2 V B 1V O V

Problem 7 An electron is placed in a uniform electric field of 0.15 N/C. Assume that the velocity of the electron is zero at t= 0. What is the velocity of the electron at t = 1 milliseconds? A) 5.3 × 10^7 m/s B) 8.8× 10^6 m/s C) 5.2× 10^7 m/s D) 2.6 × 10^7m/sE) 7.6 × 10^7 m/s

Two large aluminum plates are separated by a distance of 2.0 cm and are held at a potential difference of 195 V. An electron enters the region between them at a speed of 3.2 × 105 m/s by passing through a small hole in the negative plate and continues moving toward the positive plate. Assume the electric field between the plates is uniform. 1. What is the electron’s speed, in meters per second, when it is 0.1 cm from the negative plate?  2. What is the electron’s speed, in meters per second, when it is 0.5 cm from the negative plate?  3. What is the electron’s speed, in meters per second, when it is 1.0 cm from the negative plate?  4. What is the electron’s speed, in meters per second, when it is 1.5 cm from the negative plate?  5. What is the electron’s speed immediately before it strikes the positive plate?

An electron is placed at rest in an electric field of 510 N/C. Which of the followings is the speed of the electron 47.0 ns after being released? ( e = 1,6 × 10-19C,e, = 8,85 × 10-12c²/N.m², mej= 9,11× 10-31kg, m, = 1,67 × 10-27kg) Your answer: O A)1.4 x 105 m/s O B) 0.8 x 106 m/s O ) 0.3 x 104 m/s O D) 2.6 x 106 m/s O E)4.2 x 106 m/s

A uniform electric field exists in the region between two oppositely charged plane parallel plates. A proton is released from rest at the surface of the positively charged plate and strikes the surface of the opposite plate, 1.60 cm distant from the first, in a time interval of 1.50 × 10-6 s. a. Find the magnitude of the electric field. b. Find the speed of the proton when it strikes the negatively charged plate. Hint: Use both kinematics and electric field equations in solving the problem

A uniform electric field 3.41E3 N/C is applied in a cubic box with each side being 2.23 m long.  What is the energy stored by the electric field in the box (in J)?

3)An electron with speed 2.15×107 m/s is traveling parallel to a uniform electric field of magnitude 1.15×104 N/C . Part A How far will the electron travel before it stops? Part B How much time will elapse before it returns to its starting point?