The electric field of an electromagnetic wave traveling in vacuum is described by the following wave function: E → = (5.00 V/m) cos⎡  ⎣ kx −⎛ ⎝6.00 × 109s−1⎞⎠t + 0.40⎤⎦j^where k is the wavenumber in rad/m, x is in m, t is ins.Find the following quantities:(a) amplitude(b) frequency(c) wavelength(d) the direction of the travel of the wave(e) the associated magnetic field wave

A plane electromagnetic wave traveling in the positive direction of an x axis in vacuum has components Ex = Ey = 0 and E₂ = (4.7 V/m) cos[(x 1015 s-¹)(t-x/c)]. (a) What is the amplitude of the magnetic field component? (b) Parallel to which axis does the magnetic field oscillate? (c) When the electric field component is in the positive direction of the z axis at a certain point P, what is the direction of the magnetic field component there? Assume that the speed of light is 2.998*108 m/s. (a) Number i Units

A traveling electromagnetic wave in a vacuum has an electric field amplitude of 91.5 V/m. Calculate the intensity ? of this wave. Then, determine the amount of energy ? that flows through area of 0.0203 m2 over an interval of 15.7 s, assuming that the area is perpendicular to the direction of wave propagation.

The magnetic component of an electromagnetic wave in vacuum has an amplitude of 95.0 nT and an angular wave number of 2.49 m-1. What are (a) the frequency of the wave, (b) the rms value of the electric component, and (c) the intensity of the light?