The electric field lines tell you which way a positive charge would accelerate in that field. True O False

An electron has an initial speed of 5.21 x 106 m/s in a uniform 4.69 x 105 N/C strength electric field. The field accelerates the electron in the direction opposite to its initial velocity. (a) What is the direction of the electric field? opposite direction to the electron's initial velocity same direction as the electron's initial velocity O not enough information to decide (b) How far does the electron travel before coming to rest? m (c) How long does it take the electron to come to rest? (d) What is the electron's speed when it returns to its starting point? m/s

A proton is released from rest in a uniform electric field of magnitude 346 N/C. (a) Find the electric force on the proton. magnitude      N direction      ---Select--- in the direction of the electric field in the opposite direction of the electric field The magnitude is zero. (b) Find the acceleration of the proton. magnitude      m/s2 direction      ---Select--- in the direction of the electric field in the opposite direction of the electric field The magnitude is zero. (c) Find the distance it travels in 1.96 ?s. cm

An electron is accelerated by a constant electric field of magnitude 305 N/C. (a) Find the acceleration of the electron.   (b) Use the equations of motion with constant acceleration to find the electron's speed after 7.50  10-9 s, assuming it starts from rest.

11:05 < Back E_M_HW-2.pdf Dashboard +q 000 000 Calendar a 3 Pra 4) Four charges are an equal distance r from some origin. What is the direction of the electric field, E, at the origin, due to the four charges? Then what is the magnitude of E at the origin. Charge values are given in the picture. 12 国 To Do Q ام B Notifications Inbox

At a particular moment, a proton is 10.0 cm away from a particle with charge 121 nC. If the speed of the proton at that time is  m/s towards the  particle, then what's its speed later when the proton is only 6.00 cm away?

Part (a) Use these numbers: Q₂ = -500 nC. When the second particle is placed on the x-axis at x = +27.0 cm, it experiences a force of 1.20 N in the positive x-direction. When the second particle is moved to x = +36.0 cm on the x-axis, it experiences a force of 3.50 N in the negative x-direction. Determine the location of the mystery charge. X = cm Type your numeric answer and submit Part (b) Determine the sign and magnitude of the charge on the mystery particle. Express your answer in nanocoulombs. nC Type your numeric answer and submit ✰