The distance y = 2.3 m. Find the upward velocity of A if the downward velocity of B is 2.7 m/s. Neglect the diamete 8 m A B

The velocity of a particle moving in the x-y plane is given by (5.00i + 7.38j) m/s at time t = 3.87 s. Its average acceleration during the next 0.014 s is (2.9i+2.6j) m/s². Determine the velocity v of the particle at t = 3.884 s and the angle between the average- acceleration vector and the velocity vector at t = 3.884 s. Answers: v = ( i e = i i+ i j) m/s

If a car accelerates at 2 m/s^2 from rest along a path with a 15m radius of curvature (p ), determine its velocity and acceleration at t= 5s using normal tangent coordinates.

Given: The golf ball is struck with a velocity of 24 m/s as shown. VA = 24 m/s B Find: Distance d to where it 45° will land.