The Deligne Dam on the Cayley River is built so that the wall facing the water is shaped like the region above the curve y = 0.72² and below the line y = 120. (Here, distances are measured in meters.) The water level is 38 meters below the top of the dam. Find the force (in Newtons) exerted on the dam by water pressure. (Water has a density of 1000kg/m³, and the acceleration of gravity is 9.8m/sec².) Answer:

Determine the vertical distance of the center of gravity of the curved gate from the water surface shown in the figure. The curved gate is 5.7 m long. The values of the vertical component (Fv) and the resultant force. (F) acting on the gate are 300 kN and 400 kN asap

< A force of 190 pounds makes an angle of 78°26' with a second force. The resultant of the two forces makes an angle of 40°23' to the first force. Find the magnitudes of the second force and of the resultant. The second force has a magnitude of (Round to the nearest integer.) pounds. The resultant force has a magnitude of pounds. (Round to the nearest integer.) 40°23 78°26 190 lb B

Solve using the spefic weight of water which is 62.4 lb/ft^3