The deflection of a cantilevered beam where supporting the weight of an advertising sign is given by y = deflection at a given x location (m) W = weight of the sign (N) E = modulus of elasticity (N/m²) I = second moment of area (mª) -Wx? (3L – x) 6EI y = x = distance from the support as shown (m) L = length of the beam (m) Plot the deflection of a beam with a length of 3 m, the modulus of elasticity of E = 200 GPa, and I = 1.2 x 10° mm4 and for a sign weighing 1500 N. What is the slope of the deflection of the beam at the wall (x – 0) and at the end of the beam where it supports the sign (x = L). L Sign Problem 18.5

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
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The deflection of a cantilevered beam
where
supporting the weight of an advertising sign
is given by
y = deflection at a given x location (m)
W = weight of the sign (N)
E = modulus of elasticity (N/m²)
I = second moment of area (mª)
-Wx?
(3L – x)
6EI
y =
x = distance from the support as shown (m)
L = length of the beam (m)
Plot the deflection of a beam with a
length of 3 m, the modulus of elasticity of
E = 200 GPa, and I = 1.2 x 10° mm4 and
for a sign weighing 1500 N. What is the slope
of the deflection of the beam at the wall
(x – 0) and at the end of the beam where it
supports the sign (x = L).
L
Sign
Problem 18.5
Transcribed Image Text:The deflection of a cantilevered beam where supporting the weight of an advertising sign is given by y = deflection at a given x location (m) W = weight of the sign (N) E = modulus of elasticity (N/m²) I = second moment of area (mª) -Wx? (3L – x) 6EI y = x = distance from the support as shown (m) L = length of the beam (m) Plot the deflection of a beam with a length of 3 m, the modulus of elasticity of E = 200 GPa, and I = 1.2 x 10° mm4 and for a sign weighing 1500 N. What is the slope of the deflection of the beam at the wall (x – 0) and at the end of the beam where it supports the sign (x = L). L Sign Problem 18.5
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