The data below are from an independent-measures experiment comparing three different treatment conditions. Use an analysis of variance with α = .05 to determine whether these data indicate any significant differences among the treatments. Treatment1 Treatment2 Treatment3 0 1 4 0 4 3 0 1 6 2 0 3 M1=0.5 M2=1.5 M3=4 SS1=3 SS2=? SS3=6
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The data below are from an independent-measures experiment comparing three different treatment conditions. Use an analysis of variance with α = .05 to determine whether these data indicate any significant differences among the treatments.
Treatment1 | Treatment2 | Treatment3 |
0 | 1 | 4 |
0 | 4 | 3 |
0 | 1 | 6 |
2 | 0 | 3 |
M1=0.5 | M2=1.5 | M3=4 |
SS1=3 | SS2=? | SS3=6 |
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- The following data summarize the results from an independent-measures study comparing three treatment conditions. Treatment I II III N = 12 3 5 6 G = 60 5 5 10 ∑X2 = 392 3 1 10 1 5 6 x̅1 = 3 x̅2 = 4 x̅3 = 8 T1 = 12 T2 = 16 T3 =32…The following data summarize the results from an independent-measures study comparing three treatment conditions. Treatment I II III N = 12 3 5 6 G = 60 5 5 10 ∑X2 = 392 3 1 10 1 5 6 x̅1 = 3 x̅2 = 4 x̅3 = 8 T1 = 12 T2 = 16 T3 =32…The following data summarize the results from an independent-measures study comparing three treatment conditions. Treatment I II III N = 12 3 5 6 G = 60 5 5 10 ∑X2 = 392 3 1 10 1 5 6 x̅1 = 3 x̅2 = 4 x̅3 = 8 T1 = 12 T2 = 16 T3 =32…
- The data below are from an independent-measures experiment comparing three different treatment conditions. Use an analysis of variance with an α=.05 to determine whether these data indicate any significant mean differences among the treatment conditions (there is no need to write the answer in APA style). Treatment 1 Treatment 2 Treatment 3 0 1 6 1 4 5 0 1 8 3 2 5The following data were obtained from an independent-measures research study comparing three treatment conditions. Use an ANOVA with α = .05 to determine whether there are any significant mean differences among the treatments. Treatment I II III n = 8 n = 6 n = 4 N = 18 T = 16 T = 24 T = 32 G = 72 SS = 40 SS = 24 SS = 16 EX2 = 464The following data represent the results from an independent-measures study comparing two treatment conditions. Use an independent-measures t test with α = .05 to determine whether there is a significant mean difference between the two treatments. Use an ANOVA with α = .05 to determine whether there is a significant mean difference between the two treatments. Treatment I II 8 2 N = 10 7 3 G = 50 6 3 ΣX2 = 306 5 5 9 2 M = 7 T = 35 M = 3 T = 15 SS = 10 SS = 6
- The following data were obtained from an independent-measures research study comparing three treatment conditions. Use an ANOVA with α = .05 to determine whether there are any significant mean differences among the treatments. Treatment I II III 2 5 7 N = 14 5 2 3 G = 42 0 1 6 ΣX2 = 182 1 2 4 2 2 T = 12 T = 10 T = 20 SS = 14 SS = 9 SS = 10Post-hoc tests are necessary for an analysis of variance comparing only two treatment conditions. t or fSuppose the National Transportation Safety Board (NTSB) wants to examine the safety of compact cars, midsize cars, and full-size cars. It collects a sample of three for each of the treatments (cars types). Using the hypothetical data provided below, test whether the mean pressure applied to the driver’s head during a crash test is equal for each types of car. Use α = .05. Use a post hoc test to determine which pairs of mean are significantly different. Explain in what way are they different. Car: Compact Midsize Full-size 1 643 469 484 2 655 427 456 3 702 525 402 M 666.67 473.67 447.33 s 31.18 49.17 41.68 SS 1944.39 4835. 38 3474.45 Source SS df MS F Between 86049.556 2 43024.778 25.1749 Within 10254.22 6 1709.0367 Total 96303.776 8
- The following data represent the results from an independent-measures study comparing three treatment conditions. Treatment I II III 5 2 7 N = 24 1 6 3 G = 72 2 2 2 ∑X² = 292 3 3 4 0 5 5 1 3 2 2 0 4 2 3 5 M = 2 M = 3 M = 4 T = 16 T = 24 T = 32 SS = 16 SS = 24 SS = 20 Use an ANOVA with α = .05 to determine whether there is a significant mean difference between the two treatments. (Round to two decimal places where needed.) Source SS df MS F Fcriticalcritical Between treatments Within treatments TotalData is collected to compare two different types of batteries. We measure the time to failure of 10 batteries of each type. Battery A: mean= 8.65 Battery B: mean=11.23 Assume equal variances. Perform a .05 level test to determine if Battery B outlasts Battery A by more than 2 hours. Use Sp= .88569 What is the Chart Value for this problem?The following results are from an independent-measures, two-factor study with n = 10 participants in each treatment condition. Factor A: Factor B: A₁ A₂ B₁ n = 10 M = 4 T = 40 SS = 50 n = 10 M = 5 T = 50 SS = 60 ΣΧ2 = 640 Factor B: B₂ n = 10 M = 1 T = 10 SS = 30 n = 10 M = 2 T = 20 SS = 40