The current through the inductor of the figure is known, Calculate the voltage v(t) Report only the numerical result in millivolt (mV) The admitted tolerance is 2%. fi(t) v(t) L Dati: i(t) = -5t + 10 A. L = 5 mH. Risposta:
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- You find that a 25-F capacitor connected to 480 VAC is defective. The storeroom has no capacitors with a 480-VAC rating. However, you find two capacitors rated at 50 F and 370 VAC. Can these two capacitors be connected in such a manner that they can replace the defective capacitor? If yes, explain how they are connected and why the capacitors will not be damaged by the lower voltage rating. If no, explain why they cannot be used without damaging the capacitor.An RC series circuit is connected to a 120-V, 60-Hz power source. The resistor is 25 and has a voltage drop of 65 volts. What is the capacitance of the capacitor?A 15-F AC capacitor is connected in series with a 50 resistor. The capacitor has a voltage rating of 600 WVDC. The capacitor and resistor are connected to a 480-V, 60-Hz circuit. Is the voltage rating of the capacitor sufficient for this connection?
- You are an electrician working in an industrial plant. You discover that the problem with a certain machine is a defective capacitor. The capacitor is connected to a 240-volt AC circuit. The information on the capacitor reveals that it has a capacitance value of 10 mF and a voltage rating of 240 VAC. The only 10-mF AC capacitor in the storeroom is marked with a voltage rating of 350 WVDC. Can this capacitor be used to replace the defective capacitor? Explain your answer.A series R–L–C circuit comprises a 5µF capacitor, a 4ohm resistor and a variable inductance L. The supply voltage is 10∠0◦ V at a frequency of 159.1 Hz. The inductance is adjusted until the p.d. across the 4 ohm resistanceis a maximum. Determine for this condition (a) the value of inductance, (b) the p.d. across each component and (c) the Q-factor of the circuit.A 22-k resistor and a 0.02-F capacitor are connected in series to a 5-V source. How long will it take the capacitor to charge to 3.4 V Select one: a. 0.501 ms b. 0.66 ms c. 0.44 ms d. 0.70 ms
- Problem: 25 mH m Find Leq In below figure. 10 mH m 60 mH m 20 mH m 30 mH m -o b L 0000The capacitor dissipation factor is the ratio of inductive reactance to its resistance resistance to its inductive reactance resistance to its capacitive reactance capacitive reactance to its resistanceThe attached image shows a circuit with an AC voltage source, a resistor, inductor, and capacitor connected in series. The circuit has the following characteristics: Resistor resistance: 10 ohm Capacitor capacitance: 0.05 F Inductor inductance: 13 H Current Amplitude: 4 A Voltage amplitude across the source: 60 V Frequency at the source: 0.3 Hz Voltage amplitude across the resistor: 35 V Voltage amplitude across the capacitor: 37 V Voltage amplitude across the inductor: 80 V (a) Calculate the RMS voltages from the amplitudes above. From the RMS voltages across the capacitor, inductor and resistor, calculate the RMS voltage of the AC source. Hint: Vrms = V0/sqrt(2) Vrms = sqrt( (Vrms,R)2 + (Vrms, L - Vrms, C)2 ) (b) Calculate the RMS value of the current (c) Using the resistance, capacitance, inductance, and the frequency of the AC voltage, calculate the impedance Z. From this, and the previously measured value of Vrms, find the RMS value of the current in the circuit.
- A sinewave voltage with amplitude 2 V and frequency 1 kHz is applied capacitor. The capacitance is 0.1 uF. What is the amplitude of the current? across aWhat is the equivalent resistance ?? and what is the total inductance ??I need answer with explaination In a series R–L circuit the p.d. across the resistance R is 12V and the p.d. across the inductance L is 5V. Find the supply voltage and the phase angle between current and voltage