The current through pure inductive circuit is i= I, sin ot. Then the applied voltage v .. а. V„ sin(ox +90°) b. V, sin(ot – 60° - С. V„, sin(ex – 90°) d. V„,sin(ex + 60*) a.
The current through pure inductive circuit is i= I, sin ot. Then the applied voltage v .. а. V„ sin(ox +90°) b. V, sin(ot – 60° - С. V„, sin(ex – 90°) d. V„,sin(ex + 60*) a.
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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![The current through pure inductive
circuit is i= I, sin ot. Then the
applied voltage v =.
а.
V„ sin(or +90°)
m
b.
V, sin(or – 60*)
m
С.
V_ sin(cx – 90°)
-
d.
V„, sin(x + 60')
m
a.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff7bed94e-a15e-45d2-8814-ad3c2415c5c0%2F1817cc2f-857f-4f71-9126-5fea27855f9d%2Fe7s8cnz_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The current through pure inductive
circuit is i= I, sin ot. Then the
applied voltage v =.
а.
V„ sin(or +90°)
m
b.
V, sin(or – 60*)
m
С.
V_ sin(cx – 90°)
-
d.
V„, sin(x + 60')
m
a.
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