The Current (I) in a wire varies directly as the voltage (V) and inversely as the resistance (r). If the current is 27.5 Amps when the voltage is 110 Volts and the resistance is 40hms, find the current when the voltage is 165 volts and the resistance is 16 Ohms. (Round your answer to two decimal places.)

Answer d, e and f

a. 746 ] = Ex Effx hp b. 746(hp) I = E x Eff E voltage in volts Eff= efficiency of motor hp horsepower C. ] = (hp) 746E x Eff d. Ex Eff ] = 746(hp) NUMERIC RESPONSE 5. A motor takes 38 amperes on a 220-volt circuit. Find the horsepower output (hp) of the motor shown with an efficiency of 90%. Express the answer to the nearest hundredth. 746hp (E)(Eff) E 220 VOLTS where hp = horsepower E = voltage in volts = current in amperes Eff = efficiency 90% EFFICIENT 1=38 AMPERES I- 746 220 x0.93 Carry the answer to three decimal places.

III. The resistance of a wire carrying an electrical current varies directly to its length and inversely to the cross-sectional area. 6.) If a copper wire (which has a diameter of 0.0126 inch) has a resistance of 66.17 ohms per thousand feet, what length of this wire will produce a resistance of 33.5 ohms?