The critical T-value for a 95% confidence interval, given a sample size of 15, is closet to: Hint: Remember the significance level is simply one less the confidence interval.     2.56     1.96     2.14     1.65

The daily intakes of milk (in ounces) for ten randomly selected children were: 23.3 28.4 16.4 26.4 18.1 20.4 27.4 13.2 What is a 98% confidence interval for the population mean Then explain in a sentence what this confidence interval means ?

Use the given confidence interval to find the margin of error and the sample proportion. (0.787,0.811) (Type an integer or a decimal.) p= (Type an integer or a decimal.) E=

Here are summary statistics for randomly selected weights of newborn girls: n= 240, x= 31.8 hg, s=7.9 hg. Construct a confidence interval estimate of the mean. Use a 99% confidence level. Are these results very different from the confidence interval 29.1 hg < u< 34.7 hg with only 15 sample values, x= 31.9 hg, and s = 3.6 hg? What is the confidence interval for the population mean u? |hg < u< hg (Round to one decimal place as needed.)

10. Which one of the following statements about confidence intervals is false? A. Given the same sample of data, a 90% confidence interval will be narrower than a 95% confidence interval. B. The size of the population does not affect the width of a confidence interval. C. The population proportion determines the center of the confidence interval. D. The value of z* affects the width of a confidence interval. E. The general format of a confidence interval is “sample statistic ± margin of error.”

Use the given set of points to construct a 95% confidence interval for β1. No need to interpret the results.  x 9 6 5 9 6 12 17 11 y 25 18 15 21 21 28 30 24

ou are interested in finding a 95% confidence interval for the average commute that non-residential students have to their college. The data below show the number of commute miles for 11 randomly selected non-residential college students. Round answers to 3 decimal places where possible.   15 12 9 25 20 9 6 10 7 26 27   a. To compute the confidence interval use a distribution. b. With 95% confidence the population mean commute for non-residential college students is between  and   miles. c. If many groups of 11 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. About percent of these confidence intervals will contain the true population mean number of commute miles and about percent will not contain the true population mean number of  commute miles.

In a random sample of 1193 American adults aged 25 or older, it was found that 38.9% of them had a college degree. Construct a 98% confidence interval for the true proportion of all Americans aged 25 or older who have a college degree. Give your answers as decimals, rounded to 3 places after the decimal point (if necessary). 98% confidence interval for p:

Use the given confidence interval to find the margin of error and the sample proportion. (0.760,0.786) E = (Type an integer or a decimal.) (Type an integer or a decimal.) p =

A survey was conducted to determine the proportion of adults who approve of attempts to clone a human. Based on the response of 1000 adults a 90% confidence interval was calculated to be (0.09, 0.13). A.What is the point estimate of the true proportion of adults who approve of attempts to clone a human? B.The margin of error for the confidence interval is: