Answered: The couple moment acting on the pipe…

The couple moment acting on the pipe assembly using Cartesian vector notation. F= 25 N 300 mm 200 mm 150 mm B -F 400 mm 200 mm

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Determine the resultant and angle of concurrent forces system using algebraic method. F1=P F2=2P F3=P F4=3P F5=1P F6=2P F7=P F8=7P F9=7P 0₁-45 0₂-45 03-70 04=20 05=45 06-45 07-30 08-40 09-20 FA F5 F6 04 05 0₂ 06 F3 0₂ 0, 08 09 F₂ Fg 8 F₂ Fg F₁
The force F is applied at point A and its line of action passes through B. Determine the following: 1. The position vector of point B with respect to point A: rBA = ( i + j + k)m 2. The unit vector in the direction of vector F: u = ( i + j + k) Express your results using three significant figures.
What is the resultant moment of the five forces acting on the rod about point D?
I Review Part A Express the moment of the couple acting on the pipe assembly in Cartesian vector form. (Figure 1) Express your answer in terms of the unit vectors i, j, and k. Use the 'vec' button to denote vectors in your answers. Express your answer using three significant figures. vec ? Mc = lb · ft Figure 1 of 1 Submit Request Answer Part B 20 lb What is the magnitude of the couple moment? 3 ft Express your answer using three significant figures. B I ft 1.5 ft vec ? 20 lb 2 ft Mc = lb - ft Submit Request Answer
Q) A simplified model as shown in figure below of a planar robotic arm. You may assume that each segment has length 1.5 m, and the applied force is 250 N. 01 = 35 degree and 02 = 03 = 20 degree. Calculate the moment that the force, F, exerts .about the point A F C A M = -1042 M = -1055 M = -1050 M = -1046
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Determine the magnitude and direction of the couple moment acting on the gear shown in the figure.
Problem 3: Note: Make sure to draw all diagrams. All Units must be included. Determine the magnitude and coordinate direction angles of the resultant force and sketch this vector on the coordinate system. 3-250 N Problem 2 60 60 45 F-350 N
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The forces acting on the arm of an athlete doing shoulder exercises are shown in the figure. The athlete holds his arm at an angle of β = 30° with the horizontal axis . Point O represents the axis of rotation in the shoulder joint, point A represents the connection point of the deltoid muscle to the humerus, point B represents the center of gravity of the arm, and point C represents the application point of the force acting on the hand. The distances between the rotation axis (O point) of the shoulder joint and the points A, B and C are a=22 cm , b =33 cm and c= 60 cm , respectively . A force of F= 120 N, which makes an angle of γ=30° with the vertical from the point C, acts on the athlete's hand . Weight of the athlete's armW= 80 N. The direction of application of the Fm muscle force makes an angle of α=20° with the longitudinal axis of the arm. According to this; a) Calculate the muscle strength F M b) Calculate the angle θ of the joint reaction force F J with the horizontal.…
F1 F2 F3 A b F4 D F5 Consider the following values: - a = 25 m; b 5 m; c = 25 m; d = 5 m; F1 = 4 kN; F2 = 5 kN; F3 = 6 kN; F4 = 7 kN; F5 = 8 kN; a = 30°, 0 = 60° %3D B = 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) - 75.8 kN.m b) 32.7 kN.m c) - 14.6 kN.m d) 72.9 kN.m e) 27.1 kN.m - 66.1 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) - 198.8 kN.m b) 212.7 kN.m c) - 121.6 kN.m d) 98.9 kN.m e) 125.4 kN.m f) -170.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) - 96.7 kN.m b) 251.1 kN.m c) - 114.6 kN.m d) 217.9 kN.m 154.1 kN.m f)-177.7 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) - 198 kN.m b) 127 kN.m c) – 219 kN.m d) 369 kN.m e) 151 kN.m f) - 171 kN.m Activate V 5] What is the moment of the force F2 about point E? Go to Setting