The cost (in millions of dollars) for a 30-second ad during the TV broadcast of a major sporting event can be approximated by the rational expression 0.045x²+0.465x+1.2 x+5 where x = 0 corresponds to 1980. If this trend continues, will the cost of an ad reach $4 million by 2020? Select the correct answer below and fill in the answer box that completes your choice. OA. Yes, in 2020, the cost of an ad will be $ million. (Type an integer or decimal rounded to the nearest hundredth as needed.) OB. No, in 2020, the cost of an ad will be $ million. (Type an integer or decimal rounded to the nearest hundredth as needed.)

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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The cost (in millions of dollars) for a 30-second ad during the TV broadcast of a major sporting event can be
approximated by the rational expression
0.045x² +0.465x+1.2
x+5
where x = 0 corresponds to 1980.
If this trend continues, will the cost of an ad reach $4 million by 2020?
Select the correct answer below and fill in the answer box that completes your choice.
OA. Yes, in 2020, the cost of an ad will be $ million.
(Type an integer or decimal rounded to the nearest hundredth as needed.)
OB. No, in 2020, the cost of an ad will be $
million.
(Type an integer or decimal rounded to the nearest hundredth as needed.)
0/3
0/4
(0/
(0/
Transcribed Image Text:The cost (in millions of dollars) for a 30-second ad during the TV broadcast of a major sporting event can be approximated by the rational expression 0.045x² +0.465x+1.2 x+5 where x = 0 corresponds to 1980. If this trend continues, will the cost of an ad reach $4 million by 2020? Select the correct answer below and fill in the answer box that completes your choice. OA. Yes, in 2020, the cost of an ad will be $ million. (Type an integer or decimal rounded to the nearest hundredth as needed.) OB. No, in 2020, the cost of an ad will be $ million. (Type an integer or decimal rounded to the nearest hundredth as needed.) 0/3 0/4 (0/ (0/
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