The contents of a shark's stomach are being analyzed to determine the amount of hydrochloric acid, HCI, present in its digestive juices. A titration is performed using 0.160 M Ba(OH)2, which reacts with HCl according to the balanced equation below. If 18.45 mL of titrant is required to reach a bromthymol blue endpoint, how many moles of HCI were present in the shark's stomach juices? Ba(OH)2(aq) + 2 HCl(aq) --> 2 H20(1) + BaCl2(aq) O a 2.95e-3 5 900-6

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The contents of a shark's stomach are being analyzed to determine the amount of hydrochloric acid, HCI, present in its digestive juices. A
titration is performed using 0.160 M Ba(OH),, which reacts with HCl according to the balanced equation below. If 18.45 mL of titrant is required
to reach a bromthymol blue endpoint, how many moles of HCI were present in the shark's stomach juices?
Ba(OH)2(aq) + 2 HCl(aq) --> 2 H20(1) + Bacl>(aq)
O a
2.95e-3
O b
5.90e-6
2.95e-6
O d
5.90
e
8.67e-3
O f
5.90e-3
O g
O h
8.67e-6
2.95
Oi
8.67
Transcribed Image Text:The contents of a shark's stomach are being analyzed to determine the amount of hydrochloric acid, HCI, present in its digestive juices. A titration is performed using 0.160 M Ba(OH),, which reacts with HCl according to the balanced equation below. If 18.45 mL of titrant is required to reach a bromthymol blue endpoint, how many moles of HCI were present in the shark's stomach juices? Ba(OH)2(aq) + 2 HCl(aq) --> 2 H20(1) + Bacl>(aq) O a 2.95e-3 O b 5.90e-6 2.95e-6 O d 5.90 e 8.67e-3 O f 5.90e-3 O g O h 8.67e-6 2.95 Oi 8.67
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