the connection due to shear of The 175 x 100 x 16 mm angle shown in the figure 3.28 connected to a gusset plate with three 25 mm o bolts (A 490) when threads are excluded from shear planes. The angle (2) Compute the allowable strength failure of bolts. - (kN) consists of A 36 steel. Properties of 4175 x 100 x 16 A = 4181 mm? of the connection due to yielding of the gross section. (ASD Method) – (kN) (3) Compute the allowable strength Properties of A 490 bolts F= 276 MPa A 36 Steel Fy = N MPa F = M MPa t= L mm Nominal hole diam. = 27 mm of the connection due to fracture in the net section. (ASD Method) - (kN) (4) Compute the design strength of the connection due to yielding of the gross section. (LRFD Gusset Plate N = 280 + A M = 300 + Y 100 100 L= 15 + B Method) – (kN)

Given, Properties of 175×100×16A=4181 mm2A 36 steelFy=289 MPa Fu=332 MPa t=17 mm Properties of A 490…

Answered: the connection due to shear of The 175 x 100 x 16 mm angle shown in the figure 3.28 connected to a gusset plate with three 25 mm o bolts (A 490) when threads…

Structural Analysis

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ISBN: 9781337630931

Author: KASSIMALI, Aslam.

Publisher: Cengage,

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Question

Please answer nos. 1, 2 and 3 N=289 M=332 L=17

#1-6
(1) Compute the tensile strength of
the connection due to shear of
The 175 x 100 x 16 mm angle shown in the figure 3.28 connected to a gusset plate with
three 25 mm o bolts (A 490) when threads are excluded from shear planes. The angle (2) Compute the allowable strength
failure of bolts. - (kN)
consists of A 36 steel.
of the connection due to yielding
of the gross section. (ASD
Method) – (kN)
(3) Compute the allowable strength
of the connection due to fracture
Properties of 4175 x 100 x 16
A = 4181 mm2
Properties of A 490 bolts
F, = 276 MPa
A 36 Steel
Fy = N MPa
Fu = M MPa
t = L mm
Nominal hole diam. = 27 mm
in the net section. (ASD Method)
- (kN)
(4) Compute the design strength of
the connection due to yielding of
the gross section. (LRFD
Method) – (kN)
(5) Compute the design strength of
Gusset Plate
N = 280 + A
M = 300 + Y
100
100
50
75
100
L= 15 + B
the connection due to fracture in
the net section. (LRFD Method)
(6) Determine the block shear
strength of the connection.
(LRFD Method). – (kN)
Use U = 0.85

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