The Congressional Budget Office reports that 36% of federal civilian employees have a bachelor’s degree or higher (The Wall Street Journal).  A random sample of 120 employees in the private sector showed that 33 have a bachelor’s degree or higher.  Does this indicate that the percentage of employees holding bachelor’s degrees or higher in the private sector is less than in the federal civilian sector?  Use alpha= .05   What distribution are you using? What test are you running? What is your conclusion?

Samples of starting annual salaries for individuals entering the public accounting and financial planning professions follow. Annual salaries are shown in thousands of dollars. Public Accountant 51.2 57.8 57.3 58.2 53.2 55.0 51.9 58.5 57.0 52.9 Financial Planner 49.0 50.2 54.1 54.9 52.9 Find the value of the test statistic. W = 137.5 53.6 49.7 53.9 52.8 48.9 (a) Use a 0.05 level of significance and test the hypothesis that there is no difference between the starting annual salaries of public accountants and financial planners. State the null and alternative hypotheses. O Ho: Median salary for public accountants - Median salary for financial planners ≤ 0 H₂: Median salary for public accountants - Median salary for financial planners > 0 Ho: The two populations of salaries are identical. H₂: The two populations of salaries are not identical. O Ho: Median salary for public accountants - Median salary for financial planners 20 H₂: Median salary for public accountants - Median salary for…

12need help with parts A, D and E please

Transforming an entire distribution of scores into z-scores will not change the shape of the distribution. a. True b. False

In a normal distribution, what z-score cuts off the top 65% of the distribution?a. z = 0.7422b. z = 0.2578c. z =0.39d. z = -0.39

A study found that there was 48% chance that the driver fails a breathalyzer test when it is administered on a Friday night. The test is administered to 80 drivers. What distribution that can be used to model the above situation. How many drivers do we expect to fail the test

You decide that you want to make sure your estimate from part a is correct. You go out and gather 10 simple random samples of 25 people in your school and calculate the proportion of students within each sample whose Amazon packages arrive within two business days of ordering.  The proportion of customers that receive their packages within two days of ordering are given below.  0.70, 0.75, 0.6, 0.95, 0.90, 0.73, 0.87, 0.86, 0.92, 0.97 Explain why all of the sample proportions are not the same.

Sixty-two percent of seniors attend a particular school in a school district. Assume 500 seniors within this school district are sampled. a. Can this distribution be approximated using the Normal model? Explain. b. Use the Normal approximation to estimate the probability that at least 290 senior students are enrolled at this particular school. c. Use the Normal model to estimate the probability that between 200 and 300 senior students who are sampled are enrolled at this particular school.

A teacher asks 200 volunteers to compete a survey. Responses to the question "do you own a car" (yes or no) were recorded. Please explain why this is not a binomial distribution.

Statistics Canada conducts an annual survey to estimate the proportion of Canadians aged 20 - 24 years of age who are smokers. The most recent application of the Canadian Tobacco Monitoring Survey involved a random sample of n=496 Canadians aged 20 to 24 years of age. Each was asked for the smoking status. The number of 20 to 24 year-olds sampled who indicated they were smokers was 333.(a) Compute the sample proportion. Use at least four decimals in your answer.p^= __________ (b) Using your answer in (a), find a 97% confidence interval for pnow, the current proportion of 20 to 24 year old Canadians who are smokers, by Bootstrapping 1000 samples. Use the seed 3994 to ensure that R-Studio "randomly" samples the same "random" samples as this question will expect.You can do this by including the code, you can copy it into your R-Studio to bootstrap your samples.RNGkind(sample.kind = "Rejection");set.seed(3994);B=do(1000) * mean(resample(c(rep(1,333),rep(0,496-333)), 496));Use at least four…