College Physics
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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**Problem Statement:**

The components of a vector \( \mathbf{A} \) are \( A_X = 2.9 \) and \( A_Y = 5.3 \), and the components of a vector \( \mathbf{B} \) are given as \( B_X = 7.7 \) and \( B_Y = -10 \). What is the magnitude of the vector \( \mathbf{A} + \mathbf{B} \)?

**Answer Choices:**

- a. 12
- b. 11
- c. 13
- d. 10
- e. 9

**Solution Explanation:**

To find the magnitude of the vector \( \mathbf{A} + \mathbf{B} \), we first need to determine the components of this resultant vector. 

Given:

\[ A_X = 2.9, \quad A_Y = 5.3 \]
\[ B_X = 7.7, \quad B_Y = -10 \]

The resultant vector \( \mathbf{R} = \mathbf{A} + \mathbf{B} \) will have components:

\[ R_X = A_X + B_X = 2.9 + 7.7 = 10.6 \]
\[ R_Y = A_Y + B_Y = 5.3 + (-10) = -4.7 \]

Now, to find the magnitude of the resultant vector \( \mathbf{R} \):

\[ \| \mathbf{R} \| = \sqrt{R_X^2 + R_Y^2} = \sqrt{10.6^2 + (-4.7)^2} \]
\[ \| \mathbf{R} \| = \sqrt{112.36 + 22.09} = \sqrt{134.45} \]
\[ \| \mathbf{R} \| \approx 11.6 \]

Therefore, the closest answer choice provided is:

\[ \boxed{11} \]
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Transcribed Image Text:**Problem Statement:** The components of a vector \( \mathbf{A} \) are \( A_X = 2.9 \) and \( A_Y = 5.3 \), and the components of a vector \( \mathbf{B} \) are given as \( B_X = 7.7 \) and \( B_Y = -10 \). What is the magnitude of the vector \( \mathbf{A} + \mathbf{B} \)? **Answer Choices:** - a. 12 - b. 11 - c. 13 - d. 10 - e. 9 **Solution Explanation:** To find the magnitude of the vector \( \mathbf{A} + \mathbf{B} \), we first need to determine the components of this resultant vector. Given: \[ A_X = 2.9, \quad A_Y = 5.3 \] \[ B_X = 7.7, \quad B_Y = -10 \] The resultant vector \( \mathbf{R} = \mathbf{A} + \mathbf{B} \) will have components: \[ R_X = A_X + B_X = 2.9 + 7.7 = 10.6 \] \[ R_Y = A_Y + B_Y = 5.3 + (-10) = -4.7 \] Now, to find the magnitude of the resultant vector \( \mathbf{R} \): \[ \| \mathbf{R} \| = \sqrt{R_X^2 + R_Y^2} = \sqrt{10.6^2 + (-4.7)^2} \] \[ \| \mathbf{R} \| = \sqrt{112.36 + 22.09} = \sqrt{134.45} \] \[ \| \mathbf{R} \| \approx 11.6 \] Therefore, the closest answer choice provided is: \[ \boxed{11} \]
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