The commercial for the new Meat Man Barbecue claims that it takes 10 minutes for assembly. A consumer advocate thinks that the assembly time is different than 10 minutes. The advocate surveyed 14 randomly selected people who purchased the Meat Man Barbecue and found that their average time was 7.6 minutes. The standard deviation for this survey group was 3.9 minutes.  What can be concluded at the the αα = 0.10 level of significance level of significance? For this study, we should use    Correct The test statistic    Correct =  (please show your answer to 3 decimal places.) Based on this, we should     Correct the null hypothesis.

An educator has developed a program to improve math scores on the Texas STAAR test. The average STAAR Mathematics test for the third graders in the district was a mean= 1472. A sample of n= 30 third graders took the new math training prgram before taking the STAAR Math test. The average score for the students was M= 1497. with a standard deviation of s= 145 (note, this is standard deviation, not variance).  Was there a significant change in test scores ( use stard devistion of 0.05, two tail test).    Calculate the effect size using Cohen's d.

The mean and standard deviation of Carbon concentration is 5 mg/L and 2 mg/L based on 25 samples from a river. The mean and standard deviation of Nitrogen concentration is 7 mg/L and 3 mg/L based on 35 samples from the same river. The experimenter wants to answer the question if the Nitrogen concentration is higher than the Carbon concentration. Which of the following methods do you use? Z-test, Default Procedure Z-test, Pooled Variance Procedure T-test, Pooled Variance Procedure T-test, Default Procedure

Big babies: The National Health Statistics Reports described a study in which a sample of  96  one-year-old baby boys were weighed. Their mean weight was  25.6  pounds with standard deviation  5.3  pounds. A pediatrician claims that the mean weight of one-year-old boys is greater than  25  pounds. Do the data provide convincing evidence that the pediatrician's claim is true? Use the  =α0.05  level of significance and the  P -value method and Excel. Part: 0 / 5 0 of 5 Parts Complete   Part 1 of 5       (a)State the appropriate null and alternate hypotheses.   H0 :  =μ25 H1 :  >μ25 This hypothesis test is a ▼two-tailed test.                                                                 Part: 1 / 5 1 of 5 Parts Complete   Part 2 of 5       (b)Compute the value of the test statistic. Round the answer to at least three decimal places.…

An engineer designed a valve that will regulate water pressure on an automobile engine. The engineer designed the valve such that it would produce a mean pressure of 5.5 pounds/square inch. It is believed that the valve performs above the specifications. The valve was tested on 24 engines and the mean pressure was 5.7 pounds/square inch with a variance of 0.49. A level of significance of 0.01 will be used. Assume the population distribution is approximately normal. Make the decision to reject or fail to reject the null hypothesis.

Choose the appropriate statistical test. When computing, be sure to round each answer as indicated. A dentist wonders if depression affects ratings of tooth pain. In the general population, using a scale of 1-10 with higher values indicating more pain, the average pain rating for patients with toothaches is 6.8. A sample of 30 patients that show high levels of depression have an average pain rating of 7.1 (variance 0.8). What should the dentist determine? 1. Calculate the estimated standard error. (round to 3 decimals). [st.error] 2. What is thet-obtained? (round to 3 decimals). 3. What is the t-cv? (exact value) 4. What is your conclusion? Only type "Reject" or Retain"

A pharmaceutical company needs to know if its new cholesterol drug, Praxor, is effective at lowering cholesterol levels. It believes that people who take Praxor will average a greater decrease in cholesterol level than people taking a placebo. After the experiment is complete, the researchers find that the 4848 participants in the treatment group lowered their cholesterol levels by a mean of 21.521.5 points with a standard deviation of 2.52.5 points. The 4040 participants in the control group lowered their cholesterol levels by a mean of 20.920.9 points with a standard deviation of 4.14.1 points. Assume that the population variances are not equal and test the company’s claim at the 0.100.10 level. Let the treatment group be Population 1 and let the control group be Population 2.   Step 2 of 3 :   Compute the value of the test statistic. Round your answer to three decimal places.     step 3 of 3 :  Conclusion- fail to reject/reject...insufficient/sufficient

Urgent help needed please

Do shoppers at the mall spend more money on average the day after Thanksgiving compared to the day after Christmas? The 52 randomly surveyed shoppers on the day after Thanksgiving spent an average of $122. Their standard deviation was $29. The 59 randomly surveyed shoppers on the day after Christmas spent an average of $117. Their standard deviation was $35. What can be concluded at the αα = 0.05 level of significance? For this study, we should use        The null and alternative hypotheses would be:        H0:H0:                      H1:H1:                The test statistic     =  (please show your answer to 3 decimal places.) The p-value =  (Please show your answer to 4 decimal places.) The p-value is     αα Based on this, we should      the null hypothesis.

Unlike most packaged food products, alcohol beverage container labels are not required to show calorie or nutrient content. An article reported on a pilot study in which each of 57 individuals in a sample was asked to estimate the calorie content of a 12 oz can of beer known to contain 153 calories. The resulting sample mean estimated calorie level was 185 and the sample standard deviation was 82. Does this data suggest that the true average estimated calorie content in the population sampled exceeds the actual content? Test the appropriate hypotheses at significance level 0.001. State the appropriate null and alternative hypotheses. Ο Η : μ = 153, Ha : μ + 153 Ο Ηo : μ = 153, Ha : μ 153 Calculate the test statistic and p-value (Round your test statistic to two decimal places and your P- value to four decimal places.) z = p-value = State the conclusion in the problem context. Do not reject the null hypothesis. There is not sufficient evidence that the true average estimated calorie…