The code needs to be done in Coral please A half-life is the amount of time it takes for a substance or entity to fall to half its original value. Caffeine has a half-life of about 6 hours in humans. Given caffeine amount (in mg) as input, output the caffeine level after 6, 12, and 18 hours. Ex: If the input is 100, the output is: After 6 hours: 50.0 mg After 12 hours: 25.0 mg After 18 hours: 12.5 mg

The code needs to be done in Coral please A half-life is the amount of time it takes for a substance or entity to fall to half its original value. Caffeine has a half-life of about 6 hours in humans. Given caffeine amount (in mg) as input, output the caffeine level after 6, 12, and 18 hours. Ex: If the input is 100, the output is: After 6 hours: 50.0 mg After 12 hours: 25.0 mg After 18 hours: 12.5 mg

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter5: Control Structures Ii (repetition)

Section: Chapter Questions

Problem 20PE: When you borrow money to buy a house, a car, or for some other purpose, you repay the loan by making...

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Interest on a credit card’s unpaid balance is calculated using the average daily balance. Suppose that netBalance is the balance shown in the bill, payment is the payment made, d1 is the number of days in the billing cycle, and d2 is the number of days payment is made before billing cycle. Then, the average daily balance is: averageDailyBalance = (netBalance * d1 – payment * d2) / d1 If the interest rate per month is, say, 0.0152, then the interest on the unpaid balance is: interest = averageDailyBalance * 0.0152 Instructions Write a program that accepts as input netBalance, d1, payment, d2, and interest rate per month (interestRate). The program outputs the interest. Format your output to two decimal places. Input: 100 30 50 7 9.7 Output: 856.83 Test case 2: Input: 255.76 31 55 3 12.3 output: 3080.38
Interest on a credit card’s unpaid balance is calculated using the averagedaily balance. Suppose that netBalance is the balance shown in the bill, payment is the payment made, d1 is the number of days in the billing cycle, and d2 is the number of days payment is made before billing cycle. Then, the average daily balance is:averageDailyBalance = (netBalance * d1 – payment * d2) / d1If the interest rate per month is, say, 0.0152, then the interest on the unpaid balance is:interest = averageDailyBalance * 0.0152Write a program that accepts as input netBalance, payment, d1, d2, and interest rate per month. The program outputs the interest. Format your output to two decimal places.
Interest on a credit card’s unpaid balance is calculated using the average daily balance. Suppose that netBalanceis the balance shown in the bill, paymentis the payment made, d1is the number of days in the billing cycle, and d2is the number of days payment is made before the billing cycle. Then the average daily balance is: averageDailyBalance = (netBalance * d1 –payment * d2) / d1 if the interest rate per month is say, 0.0152, then the interest on the unpaid balanceis: interest = averageDailyBalance * 0.0152 Design a program that accepts as input netBalance, payment, d1, d2, and interest rate per month. The program outputs the interest charged. Format your output to two decimal places. C++
Interest on a credit card’s unpaid balance is calculated using the average daily balance. Suppose that netBalance is the balance shown in the bill, payment is the payment made, d1 is the number of days in the billing cycle, and d2 is the number of days payment is made before billing cycle. Then, the average daily balance is: averageDailyBalance = (netBalance * d1 – payment * d2) / d1 If the interest rate per month is, say, 0.0152, then the interest on the unpaid balance is: interest = averageDailyBalance * 0.0152 Write a program that accepts as input netBalance, d1, payment, d2, and interest rate per month (interestRate). The program outputs the interest. Format your output to two decimal places.
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The quadratic formula is used to solve a very specific type of equation, called aquadratic equation. These equations are usually written in the following form:ax2 + bx + c = 0The Quadratic Formula x = ( -b ± √( b^2 - 4ac ) ) / ( 2a ) Where a, b, and c are constants with a ≠ 0. (If a = 0, the equation is a linear equation.)The discriminant is the part of the formula in the square root. If the value of the discriminant is zero then the equation has a single real root. If the value of thediscriminant is positive then the equation has two real roots. If the value of thediscriminant is negative, then the equation has two complex roots.Write a program that finds the roots of the quadratic equation using the Quadratic Formula. Write a function named discriminant in the file, Disc.py, to calculate and return the discriminant of the formula. Let the main function call the discriminant function and then calculate the solution(s) of the equation. Do not calculate the solutions in the discriminant…
Exercise III: Catalan numbers For n e N, denote by c, to be the number of ways to form a "mountain range" with n upstrokes (U) and n downstrokes (D) that all stay above a horizontal line. For instance: for n = 1, only UD is allowed, so c = 1; • for n = 2, only UUDD and UDUD are allowed, so c2 = 2. 1. Check that c3 = 5 by writing down or drawing all possible options. 2. Consider the power series +00 g(x) = 2 n=0 (by definition co = 1) called the generating function of the sequence (en). Justify that cn < 4" for each n, and deduce that the radius of convergence of g is at least 1/4. 3. It can be show that for r E (-1/4, 1/4), g(x) = 1+ xg(r)? and therefore 1- VI 4.x g(x) = 2.x Use this formula and the known power series of V1+ x to write the first terms of the power series expansion of g, in the form g(x) = co + c1x + c2x2 + C3x + c4x* + ·.. Show how you obtain a few terms, but you do not need to show all computations and you can use a calculator for fractions. Check that you recover co,…
A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: The year must be divisible by 4 If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year. Ex: If the input is 1712, the output is: 1712 is a leap year. Ex: If the input is 1913, the output is: 1913 is not a leap year. 1 2 3 4 5 6 7 8 9 10 11 Put("{} is a leap year.".format(i_year)) print("{} is not a leap year.".format(i_year)) inputYear = Get next input What would be the code?
Computer Science CS220 – Programming Project – P07: Brute Force Equation Solver Project Specifications: For every value of x from -10 to 10 For every value of y from -10 to 10 Check if the current x and y satisfy both equations. If so, output the solution, and finish. Ex: If no solution is found, output: You can assume the two equations have no more than one solution. Note: Elegant mathematical techniques exist to solve such linear equations. However, for other kinds of equations or situations, brute force can be handy. in c++ please using namespace std;
In python, a) In the Hi-Lo game, the player begins with a score of 1000. The player is prompted for the number of points to risk and a second prompt asks the player to choose either High or Low. The player’s choice of either High or Low is compared to a random number between 1 and 13, inclusive. If the number is between 1 and 6 inclusive, then it is considered “low”. A number between 8 and 13 inclusive is “high”. The number 7 is neither high nor low, and the player loses the points at risk. If the player had guessed correctly, the points at risk are doubled and added to the total points. For a wrong choice, the player loses the points at risk. Create a HiLo application based on this specification. Application output should look similar to b) Modify the application to allow the player to continue until there are 0 points left. At the end of the game, display the number of guesses the user took before running out of points.
Question Using Java programming language write a program to manage a hotel with 24 rooms;10 rooms are Executive, with price Gh ₵ 2500.00 per night,7 rooms are Chalets, with amounts Gh ₵ 1500.00 per night7 rooms are Ordinary, with amount Gh ₵ 500.00 per night The program should allow customers to book for rooms for a number of nights, and update the number of empty rooms available for each category when a customer has paid fully and has checked-in; also update the number of empty rooms available when customer checks-out.Customers should make bookings with their first names, telephone number A customer should be prompted to know if a room is booked (meaning a another customer has booked it but has not paid fully, or has not checked-in) A customer should be prompted to know if a room is occupied (meaning a booked room has been fully paid for, or the customer has checked-in) A customer should be prompted to know if a room is available (meaning a room has neither been booked nor…
Scenario As you surely know, due to some astronomical reasons, years may be leap or common. The former are 366 days long, while the latter are 365 days long. Since the introduction of the Gregorian calendar (in 1582), the following rule is used to determine the kind of year: if the year number isn't divisible by four, it's a common year, otherwise, if the year number isn't divisible by 100, it's a leap year. otherwise, if the year number isn't divisible by 400, it's a common year. otherwise, it's a leap year. none of the above year int(input("enter the year")) if (year%4 1-0) and (year%400 -0) or (year % 1000): print (year is common year") else: print(year, is leap year") year= int(input ("enter the year")) if (years !-0) or (year480 1-0) and (year % 1001-0): print(year is common year") else: print(year, "is leap year") D year= int(input("enter the year"))