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The circle x² + y² - 18x + 8y +48=0 is translated one unit right and two units down. Which is the radius and center of the translated circle? Center (9,-4); r = 7 Center (9,-4); r=49 O Center (10,-6);r=7 Center (10,-6); r = 49 O

The circle x² + y² - 18x + 8y +48=0 is translated one unit right and two units down. Which is the radius and center of the translated circle? Center (9,-4); r = 7 Center (9,-4); r=49 O Center (10,-6);r=7 Center (10,-6); r = 49 O

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Question:** The circle \( x^2 + y^2 - 18x + 8y + 48 = 0 \) is translated one unit right and two units down. Which is the radius and center of the translated circle? **Answer Choices:** 1. Center (9, -4); \( r = 7 \) 2. Center (9, -4); \( r = 49 \) 3. Center (10, -6); \( r = 7 \) 4. Center (10, -6); \( r = 49 \) The formula for the translation of a circle involves shifting the center by the given units. The original circle has to be rewritten in its standard form to identify its center and radius before translation can be applied.
Transcribed Image Text:**Question:** The circle \( x^2 + y^2 - 18x + 8y + 48 = 0 \) is translated one unit right and two units down. Which is the radius and center of the translated circle? **Answer Choices:** 1. Center (9, -4); \( r = 7 \) 2. Center (9, -4); \( r = 49 \) 3. Center (10, -6); \( r = 7 \) 4. Center (10, -6); \( r = 49 \) The formula for the translation of a circle involves shifting the center by the given units. The original circle has to be rewritten in its standard form to identify its center and radius before translation can be applied.
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