The Cartesian vector form of the moment produced by force F, about point O is equal to. 1 ft -2 ft- -y 3 ft F = (-20i + 10j + 30k} lb 2 ft F = |-10i – 30j + 50k} Ib

Find the moments of the forces as shown in figure 3 about point O.

Untitled Section F1 F2 a F3 d F4 Consider the following values: - F5 a = 16 m; b = 11 m; c = 13 m; d = 8 m; F1 = 3 kN; F2 = 11 kN; F3 = 2 kN; F4 = 20 kN; F5 = 2 kN; a = 30° , 0 = 60° , B = 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) 88.8 kN.m b) 76.3 kN.m c) 19.6 kN.m d) 55.5 kN.m e) 59.1 kN.m f) 81.3 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) 88.8 kN.m b) 120.8 kN.m c) 31.6 kN.m d) 98.9 kN.m e) 41.1 kN.m f) 24.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) 125.7 kN.m b) 178.1 kN.m c) 254.6 kN.m d) 439.1 kN.m e) 144.1 kN.m f) 215.3 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) 77.8 kN.m b) 98.3 kN.m c) 100.6 kN.m d) 18.9 kN.m e) 97.1 kN.m f) 60.1 kN.m 5] What is the moment of the force F2 about point E? Activate V ) 151.3 kN.m Go to Setting! a) 122.7 kN.m b) 108.1 kN.m c) 66.6 kN.m d) 83.1 kN.m e)…

1: The force vector F=250i-50j-550k Ib acts at point B. Calculate the moment generated by this force about point O. F 8 ft 1.5 ft 0.25 ft