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The carbon-14 decay rate of a sample obtained from a young tree is 0.260 disintegration per second per gram of the sample. Another wood sample prepared from an object recovered at an archaeological excavation gives a decay rate of 0.181 disintegration per second per gram of the sample. What is the age of the object? (The half-life of carbon-14 is 5715 years.) x 10 years Enter your answer in scientific notation.

The carbon-14 decay rate of a sample obtained from a young tree is 0.260 disintegration per second per gram of the sample. Another wood sample prepared from an object recovered at an archaeological excavation gives a decay rate of 0.181 disintegration per second per gram of the sample. What is the age of the object? (The half-life of carbon-14 is 5715 years.) x 10 years Enter your answer in scientific notation.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Be sure to answer all parts. The carbon-14 decay rate of a sample obtained from a young tree is 0.260 disintegration per second per gram of the sample. Another wood sample prepared from an object recovered at an archaeological excavation gives a decay rate of 0.181 disintegration per second per gram of the sample. What is the age of the object? (The half-life of carbon-14 is 5715 years.) x 10 years Enter your answer in scientific notation.
Transcribed Image Text:Be sure to answer all parts. The carbon-14 decay rate of a sample obtained from a young tree is 0.260 disintegration per second per gram of the sample. Another wood sample prepared from an object recovered at an archaeological excavation gives a decay rate of 0.181 disintegration per second per gram of the sample. What is the age of the object? (The half-life of carbon-14 is 5715 years.) x 10 years Enter your answer in scientific notation.
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