Structural Analysis
Structural Analysis
6th Edition
ISBN: 9781337630931
Author: KASSIMALI, Aslam.
Publisher: Cengage,
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I need detailed help solving this exercise from Applied Mechanics.
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The car rests on four scales and in this position the scale readings of both the front
F and F, as indicated in Fig. 4(a). Note that the tires
and rear tires are shown by
each have a diameter of
significant figures].
A
1.98 ft. [Note: Present your final results in three
(a) Find the location to the gravity center G of the car indicated in Fig. 4(a).
(b) When the rear wheels are elevated to a height of 3 ft above the front scales, the
new readings of the front wheels are also recorded, as indicated in Fig. 4(b). Find
the inclination angle of the car with respect to the horizontal direction.
(c) Find the location y to the gravity center G of the car indicated in Fig. 4(a) from
equilibrium.
B
FB
=975 lb + 984 lb
=
3.0 ft
9.40 ft
Fig. 4(a)
= 1129 lb + 1168 lb = 2297 lb
FA
1959 lb
G
B
Fig. 4(b)
FA=
=1269 lb + 1307 lb
= 2576 lb
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Transcribed Image Text:The car rests on four scales and in this position the scale readings of both the front F and F, as indicated in Fig. 4(a). Note that the tires and rear tires are shown by each have a diameter of significant figures]. A 1.98 ft. [Note: Present your final results in three (a) Find the location to the gravity center G of the car indicated in Fig. 4(a). (b) When the rear wheels are elevated to a height of 3 ft above the front scales, the new readings of the front wheels are also recorded, as indicated in Fig. 4(b). Find the inclination angle of the car with respect to the horizontal direction. (c) Find the location y to the gravity center G of the car indicated in Fig. 4(a) from equilibrium. B FB =975 lb + 984 lb = 3.0 ft 9.40 ft Fig. 4(a) = 1129 lb + 1168 lb = 2297 lb FA 1959 lb G B Fig. 4(b) FA= =1269 lb + 1307 lb = 2576 lb
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