Structural Analysis
6th Edition
ISBN: 9781337630931
Author: KASSIMALI, Aslam.
Publisher: Cengage,
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- Question 2: An unsymmetrical flexural member consists of a 3 × 22 top flange, a 3 × 16 bottom flange, and a ½ × 66 web. a. Determine the distance ỹ from the top of the shape to the horizontal plastic neu- tral axis. b. If A572 Grade 50 steel is used, what is the plastic moment M, for the horizontal plastic neutral axis? c. Compute the plastic section modulus Z with respect to the minor principal axis.arrow_forwardQuestion 4 Complete the table below for the steel sections shown. All sections are bending about their horizontal axis. Section Location hep Ney Slenderness (show calculations) of element bf Flange te ld ++ tw be = 800 mm Web tf = 20 mm d = 1440 mm tw = 16 mm Grade 300, heavily 入。= Whole Asp= Asy= welded plates section br Flange tr d Web bf = 800 mm te = 20 mm d = 1420 mm tw = 16 mm Grade 300, heavily welded plates 入。= Whole Asp= Asy= sectionarrow_forward3. The aluminum block has the rectangular cross-section and is subjected to an axial compressive force of 8 kips. The 1.5-in side changed its length to 1.50014 inches. Use E = 10 x 103 ksi. Calculate the new Answer: Lnew = 2.00019 in length of the 2-inch side. 1.5 in 2 in. 8 kip- 8 kip 3 in.arrow_forward
- The lap joint of a tension member is shown. The plate is 252mm wide and 12mm thick. The bolts are 20mm in diameter and the holes are 3mm larger than the bolt diameter. Steel A36 with Fy = 248 MPa and Fu = 400Mpa. It is required to determine the capacity of the joint based on gross area, net area, and block shear. a.) Determine the safe value of P based on gross area: Use Ft = 0.6Fy b.) Determine the safe value of P based on tension net area: Use Ft = 0.5Fyarrow_forwardP,= 500 k J. P, = 1,000 k I P,= 500 k Py=1,000 k fixed fixed Check whether a 17 ft W 14 x 211 section of A992 steel can safely carry the given applied service loads pinned 35 ft 18 ft pinned pinned Strong Axis Weak Axisarrow_forwardPlease write the solution on paper.arrow_forward
- Use A992 steel and select the lightest W shape. Use any design procedure.a. Use LRFD.b. Use ASD.arrow_forwardHand written and clean writing please .arrow_forwardQuestion # 1: Determine the force in each member of the truss and state if the members are in tension or compression. 300 lb 600 15 B 60015 GOO G 11. 244in. 6 ft load at point B, D, F = 600 lb load at pount A and H=300 lb distance AC = CE =EG = GH = 8FT -80---SA- [Answer: FAB=15001b-C. Fac-12001b-T, Fac0, For-12001b-T, Fan+ 12001b-C, F₁-601b-C. Form 721h-T, Use symmetry to obtain the rest of the members]arrow_forward
- please show me a complete solution. Thank youarrow_forwardDetermine the force in each member of the truss shown by the method of joints. Show free body diagram and handwritten solution. Please make sure it is correct answer. Thank you!arrow_forwardGiven the truss shown, solve the following. Use A36 steel and assume there are two lines of three 19 mm bolts in each flange. Hole diameter is assumed to be three mm more than the bolt diameter. Neglect the weight of the section. a.What is the capacity of member CG? b. Design member CG using a W section. c. What is the tensile capacity of the section for CG based on gross area? The following W Section were considered for the design: W10x33 W14x38 W8x40 W16x36 W10x39 W8x13 189 KN 1.50 HL B 145 KN 1.50 E + 137 KN 121 KN -3.00 + 12.00 3.00 154 KN + W4x13 W6x9 W10x12 200 KN -1.50 1.50 1 030 T 1.20 +2.40 0.60 L i 0.30arrow_forward
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