The cable BC carries a tension of 750 N. Determine the projection of the tension on the line BO and find the angle between them. 1.2 m 1.6 m с 0.7 m 30 OT BO=555.16 N,0=42.25 OT BO 500.16 N,0=25.25 OT BO=-598i+411j+189.5k N,0=42.25 0.8 m
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