MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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- A sample mean for a treated group of n = 9 individuals is 32 and the population mean for the untreated group is 26. If the sample standard deviation is 9 ( is unknown), which of the following test statistics is correct? O z = .67 O z = 2.0 Ot=.67 O t = 2.0arrow_forward1. Scores from a questionnaire measuring social anxiety form a normal distribution with a mean of m = 50 and a standard deviation of s = 10. What is the probability of obtaining a sample mean greater than X(sample mean) = 53, for a random sample of n = 4 people? a. .2743 b. .2776 c. .2578 d. .2611arrow_forwardUse the following information to answer questions 1, 2, and 3. 1. Suppose that x has a normal distribution with a mean of 20 and a standard deviation of 3. Random samples of size 36 are drawn. What is the probability that the next time x is measured that it will have a value less than 16? 2.What is the probability that the next sample taken will have an average value greater than 20.5? 3.What is the probability that the next sample taken will have an average value less than 17?arrow_forward
- 3. Determine the following from the graph. Show all your work. a. Determine the mean and standard deviation: PDF of a Random Variable ū 6.09 COM 0.04 · b) Draw a qualitative sketch of the CDF of the distribution shown. Be sure to show axis values and key values that are appropriate! 0 10 c) What type of distribution was the PDF of a Random Variable?arrow_forwardA variable of a population has a mean of µ = 82 and a standard deviation of o = 9. a. Identify the sampling distribution of the sample mean for samples of size 81. b. In answering part (a), what assumptions did you make about the distribution of the variable? c. Can you answer part (a) if the sample size is 25 instead of 81? Why or why not? a. What is the shape of the sampling distribution? normal uniform skewed O bimodal What is the mean of the sampling distribution? Hi = (Simplify your answer.) What is the standard deviation of the sampling distribution? (Simplify your answer.) b. In answering part (a), what assumptions did you make about the distribution of the variable? A. It was assumed that the variable was normally distributed. B. No assumptions were made because, for a relatively large sample size, the sampling distribution is normal, regardless of the distribution of the variable under consideratioarrow_forward': Consider a puzzle is created where the amount of time it takes an individual to solve the puzzle follows a normal distribution with a standard deviation of 2 minutes. a) If a sample of 13 individuals was collected, what is the probability the sample mean time required to solve the puzzle would be within 1.2 minutes of the population mean? b) What would the required sample size be if we wanted the sample mean to be within half a minute of the population mean with a probability of .9?arrow_forward
- The amount of pollutants that are found in waterways near large cities is normally distributed with mean 8.7 ppm and standard deviation 1.7 ppm. 18 randomly selected large cities are studied. Round all answers to 4 decimal places where possible. a. What is the distribution of X? X N( b. What is the distribution of T? I - N( c. What is the probability that one randomly selected city's waterway will have more than 8.9 ppm pollutants?arrow_forwarda. Determine the sampling distribution of the sample mean for samples of size 3. Interpret your answer in terms of the distribution of all possible sample mean brain weights for samples of three men. The mean of the sample mean is μx=1.401.40kg. (Type an integer or a decimal. Do not round.) The standard deviation of the sample mean is σx=0.06350.063kg. (Round to four decimal places as needed.) Interpret these answers in context. For samples of three men, the individual brain weights have a normal distribution with a mean of 1.41.4 kg and a standard deviation of 0.06350.0635 kg. (Type integers or decimals rounded to four decimal places as needed.)arrow_forwardIf someone could help me answer this that would be great.arrow_forward
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