The body on the 30° incline is acted upon by a force P inclined at 20° with the horizontal. If P is resolved into componentsparallel and perpendicular to indine and the value of the parallel component is 1350 N, compute the value of theperpendicular component.A) 1680.33NB)1608.87 N(c) 1630.80 ND) 11806.62 N

Answered: Image /qna-images/answer/ada1d53b-0033-4538-8216-0a1950be8a8b.jpg

The body on the 30° incline is acted upon by a force P inclined at 20° with the horizontal. If P is resolved into components parallel and perpendicular to indline and the value of the parallel component is 1350 N, compute the value of the perpendicular component. )1680.33 N B )1608.87 N C) )1630.80N 1806.62 N

The body on the 30° incline is acted upon by a force P inclined at 20° with the horizontal. If P is resolved into components parallel and perpendicular to indline and the value of the parallel component is 1350 N, compute the value of the perpendicular component. )1680.33 N B )1608.87 N C) )1630.80N 1806.62 N

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

1. Determine the equations of slope and deflection. 2. Determine the slope and deflection at point 3m from point A. E =210 GPa. 100 | Cross section 6KN.m 2m B8KN 2 kN/m 2m T ) B8KN 2m
5. The body on the 30°incline is acted upon by a force P inclined at 20°with the horizontal. If P is resolved into components parallel and perpendicular to the incline and the value of the parallel component is 300 N, compute the value of the perpendicular component and of P.
Use conjugate beam method to determine the slope at C. Where El=100,000KN/m^2 1OOKN A AAm C RB
The body on the 25° Incline in the flgure below is acted upon by a force P Inclined at 15° with the horizontal. If P is resolved Into components parallel and perpendicular to incline and the value of the parallel component is 1800 N, compute the value of the perpendicular component and that of P. 15 25°
Problem Set - 2: The simply supported steel beam is loaded by the 20 kN-m couple as shown in the figure. Using E = 200 GPa and I = 8x106mm², determine the displacement and slope at the point where the couple is applied. Use Double Integration A 6m 20 kN-m B 4m C
Given the value of the semi-major axis, a = 6377802 m. and 1/f = 290.8642 where f is the flattening of the spheres if. Compute the semi-minor axis of the shperiod.
How to come up to Iz (m,n)= 0.10685
please solve 16 with the information from 14....... Asap plzzz
Calculate the vertical deflection of point B and the horizontal movement at D shown in the figure. Consider that all the elements of the truss are linearly elastic and have sectional areas of 1800mm2. Also consider an E of 200,000N/mm2. Add the calculation process of solving the problem step by step and complete the table accordingly. L F FB ∂FB / ∂PB FD ∂FD/∂PD AE - 2√2/3 PB -2/3 √2 EB EF AB BC CD BF FD FC
Compute the y-component of the resultant of the concurrent forces shown in N. P1 = 214 N, P2 = 421 N, P3 405 N, P4 = 183 N, 01 = 15, 02 = 34, and 03 = 33. Write numerical value only in 2 decimal places. P1 P4 = 03 0₂ + Y 0₁ P3 P2 +X
Situation #1 A 3 m El is Constant (Assume El = 1 kN-m²) Y KN ny 10 + A X_kN Fam B Determine the slope at A Determine the slope at B Determine the location of the maximum deflection from A Determine the maximum deflection X= 329 Y= 29 A= 8
Assume that w = 73 N/m, L = 2 m, and EI is constant for the beam. Find the slope at the midpoint x = L/2 of the beam. 91.9/EI 85.2/EI 108.3/EI 51.4/EI 98.6/EI