The block is at rest as shown. What is the peiod of the oscillation if the block is pulled down by 10 cm, in seconds? Use g = 10 m/s². Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement. 100 g ā 8

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
icon
Related questions
icon
Concept explainers
Question
**Question:**

The block is at rest as shown. What is the period of the oscillation if the block is pulled down by 10 cm, in seconds? Use \( g = 10 \, \text{m/s}^2 \).

*Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer; it is already given in the question statement.*

**Diagram Explanation:**

The diagram shows a vertical spring with a block attached to its lower end. The following details are included in the diagram:

- A vertical ruler is positioned adjacent to the spring, marked from 0 to 100 cm.
- The scale indicates various measurements on the ruler at 10 cm increments.
- The block, labeled as "100 g," hangs from the spring at a point slightly below the 90 cm mark.
- The spring is slightly stretched due to the weight of the block.

This setup illustrates a typical spring-mass system used to study oscillations and the effect of gravity on a suspended mass.
Transcribed Image Text:**Question:** The block is at rest as shown. What is the period of the oscillation if the block is pulled down by 10 cm, in seconds? Use \( g = 10 \, \text{m/s}^2 \). *Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer; it is already given in the question statement.* **Diagram Explanation:** The diagram shows a vertical spring with a block attached to its lower end. The following details are included in the diagram: - A vertical ruler is positioned adjacent to the spring, marked from 0 to 100 cm. - The scale indicates various measurements on the ruler at 10 cm increments. - The block, labeled as "100 g," hangs from the spring at a point slightly below the 90 cm mark. - The spring is slightly stretched due to the weight of the block. This setup illustrates a typical spring-mass system used to study oscillations and the effect of gravity on a suspended mass.
**Problem Statement:**

A simple pendulum of mass \( m = 2.00 \, \text{kg} \) and length \( L = 0.82 \, \text{m} \) on planet X, where the value of \( g \) is unknown, oscillates with a period \( T = 1.70 \, \text{s} \). What is the period if the length is doubled?

**Options:**

- \( 2.4 \, \text{s} \)
- \( 0.85 \, \text{s} \)
- \( 1.2 \, \text{s} \)
- \( 1.7 \, \text{s} \)
- \( 3.4 \, \text{s} \)

This question is designed to test your understanding of the relationship between the length of a pendulum and its period of oscillation. The period of a simple pendulum is given by the formula:

\[
T = 2\pi \sqrt{\frac{L}{g}}
\]

Where:
- \( T \) is the period,
- \( L \) is the length of the pendulum,
- \( g \) is the acceleration due to gravity.

If the length \( L \) is doubled, we need to determine the new period.
Transcribed Image Text:**Problem Statement:** A simple pendulum of mass \( m = 2.00 \, \text{kg} \) and length \( L = 0.82 \, \text{m} \) on planet X, where the value of \( g \) is unknown, oscillates with a period \( T = 1.70 \, \text{s} \). What is the period if the length is doubled? **Options:** - \( 2.4 \, \text{s} \) - \( 0.85 \, \text{s} \) - \( 1.2 \, \text{s} \) - \( 1.7 \, \text{s} \) - \( 3.4 \, \text{s} \) This question is designed to test your understanding of the relationship between the length of a pendulum and its period of oscillation. The period of a simple pendulum is given by the formula: \[ T = 2\pi \sqrt{\frac{L}{g}} \] Where: - \( T \) is the period, - \( L \) is the length of the pendulum, - \( g \) is the acceleration due to gravity. If the length \( L \) is doubled, we need to determine the new period.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Knowledge Booster
Estimate of calculation
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
University Physics (14th Edition)
University Physics (14th Edition)
Physics
ISBN:
9780133969290
Author:
Hugh D. Young, Roger A. Freedman
Publisher:
PEARSON
Introduction To Quantum Mechanics
Introduction To Quantum Mechanics
Physics
ISBN:
9781107189638
Author:
Griffiths, David J., Schroeter, Darrell F.
Publisher:
Cambridge University Press
Physics for Scientists and Engineers
Physics for Scientists and Engineers
Physics
ISBN:
9781337553278
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Lecture- Tutorials for Introductory Astronomy
Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:
9780321820464
Author:
Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:
Addison-Wesley
College Physics: A Strategic Approach (4th Editio…
College Physics: A Strategic Approach (4th Editio…
Physics
ISBN:
9780134609034
Author:
Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:
PEARSON