The battery shown in the circuit below has AV = 10.0 V, resistors R₁ = 8.44 kQ2, R2 = 8.52 kQ, and R3 = 7.69 k2, where 1 ΚΩ kQ 103. The current flowing out of the battery (and then from point b to c through R₁) is I₁, the current flowing from c to d through R₂ is l₂, and the current flowing from e to f through R, is l3-

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Chapter29: Direct Current (dc) Circuits
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The battery shown in the circuit below has AV = 10.0 V, resistors R₁ = 8.44 k2, R2 = 8.52 k, and R3 = 7.69 k, where 1
k=103 2. The current flowing out of the battery (and then from point b to c through R₁) is I₁, the current flowing from c
to d through R2 is 12, and the current flowing from e to f through R3 is 13.
b
AV
R₁
R3
R2
a
d
f
Calculate the power dissipated by resistor R2. Give your answer in units of milli-watts (1.0 mW = 103 W) with two decimal
places.
Answer:
Check
Transcribed Image Text:The battery shown in the circuit below has AV = 10.0 V, resistors R₁ = 8.44 k2, R2 = 8.52 k, and R3 = 7.69 k, where 1 k=103 2. The current flowing out of the battery (and then from point b to c through R₁) is I₁, the current flowing from c to d through R2 is 12, and the current flowing from e to f through R3 is 13. b AV R₁ R3 R2 a d f Calculate the power dissipated by resistor R2. Give your answer in units of milli-watts (1.0 mW = 103 W) with two decimal places. Answer: Check
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