The base of a three-dimensional figure is bound by the line y = 4 - x on the interval [-2, 2]. Vertical cross-sections that are perpendicular to the x-axis are right triangles with height equal to 4. Algebraically, find the area of each triangle. 3-2-1 1 2 3 4 5 6 7 ○ A(x) = (4 − x) ○ A(x) = (4 − x)² O A(x) = 2 (4 − x) O A(x) = 2 (4 + x)

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter2: Equations And Inequalities
Section2.3: Quadratic Equations
Problem 50E
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The base of a three-dimensional figure is bound by the line y = 4 - x on the interval [-2, 2]. Vertical cross-sections that are perpendicular
to the x-axis are right triangles with height equal to 4.
Algebraically, find the area of each triangle.
-3-2-11- 1 2 3 4 5 6 7
X
o A(x) = (4x)
○ A(x) = (4x)²
O A(x) = 2 (4 − x)
O A(x) = 2 (4 + x)
Transcribed Image Text:The base of a three-dimensional figure is bound by the line y = 4 - x on the interval [-2, 2]. Vertical cross-sections that are perpendicular to the x-axis are right triangles with height equal to 4. Algebraically, find the area of each triangle. -3-2-11- 1 2 3 4 5 6 7 X o A(x) = (4x) ○ A(x) = (4x)² O A(x) = 2 (4 − x) O A(x) = 2 (4 + x)
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