the balanond three phase paralel cireuit belew.complete the tables uing the provided values Assuming sa sequence strietly une stered values throughout the computationa. Provide up to fur decimal places Note: Neglect watmeter range mtipller
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- Problem 1 - Series en Parallel AC networks [19] Look at the circuit in Figure 1 and determine the following: (a) Total Admittance. (b) Total Impedance. (c) Total Current (l:). (d) Current (I1) through impedance Z2. (e) Current (12) through impedance Z3. (f) Current (I3) through impedance Z4. (g) Is this an inductive or capacitive circuit? A. B Zs 220V;50HZ Figure 1 (h) Voltage across Z1. (i) Voltage across A and B. G) Voltage across Zs. Z1 = 3 + j5 ohm Z2 = 10 + jo ohm Z3 = 5 + j15 ohm Z4 = 10 – j30 ohm Zs = 20 – j30 ohm Admittance and Impedance in rectangular notation. All currents and voltage in polar notation. Take voltage as reference.7. Three load units A, B, and Care connected in parallel and take currents that are respectively 11 A, 10A and 15A. Assuming IA to be the reference phasor, IB leads IA by 30degrees and IC legs behind IA by 65degrees. Calculate the total (resultant) currentand angle it makes with the x-axis.Differentiate Wye and Delta Connection in Three Phase System and Relate it with Computer Engineering
- The circuit shows an unbalanced electrical installation powered by a positive sequence symmetrical three-phase network of 380 V compound voltage. The loads are single phase. Load 1 absorbs an active power of 950 W with f.d.p. 0.5 inductive. Load 2 absorbs an active power of 1,140 W with f.d.p. Unit. Load 3 absorbs from the network an active power of 760 W with f.d.p. 0.5 capacitive. Taking the network voltage URN as the phase reference, calculate: a) complex expressions of the line currents IR. Is. and ITThe figure shows a 3-phase bala Time left 1:06:30 200 /00 Vrms. sequence electrical system. Vcn Vbn %3D al Balanced (-) sequence 100 so a 2000 Vms Select one: O a. 200 /-120 Vrms O b. 200 v2 /0 Vrms O C. 200 /0 Vrms O d. 200 v2/-120 Vrms e. 200/120 VrmsThe circuit shows an unbalanced electrical installation powered by a positive sequence symmetrical three- phase network of 380 V compound voltage. The loads are single phase. Load 1 absorbs an active power of 950 W with f.d.p. 0.5 inductive. Load 2 absorbs an active power of 1,140 W with f.d.p. Unit. Load 3 absorbs from the network an active power of 760 W with f.d.p. 0.5 capacitive. Taking the network voltage URN as the phase reference, calculate: a) complex expressions of the line currents IR. Is. and IT RO- SO TO IR Is IT U₁-380 V CARGA 1 P₁ =950 W cos p1=0,5 ind. CARGA 2 P₂=1.140 W cos p₂=1 CARGA 3 P3=760 W cos p3=0,5 cap.
- A three-phase system has balanced conditions so that the per-phase circuit representation can be used as shown in Figure 1 Select the turns ratio of the step-up and step-down transformers that the system operates with an efficiency greater than 99 percent. Moreover, find the complex power (received or given) of all components in the circuit and the V1 and V2 voltages. The load voltage is specified as 4 kV rms, and the load impedance is 4/3 ohm. ..X₂=0.1 1 XL +03 Soto X₁ = 0.2 X = 0.1 X = 0.1 Above is the one-line diagram of a simple power system. Each generator is represented by an emf behind the subtransient reactance. All impedances are expressed in per unit on a common base. All resistances and shunt capacitance are neglected. The generators are operating on no load at their rated voltage with their emfs in phase. A symmetrical fault occurs at bus 1 through a fault impedance Z, =j0.08 per unit. a) Using Thevenin's Theorem, determine the impedance to the point of fault and the fault current in per unit. b) Find the bus voltages and line currents during the fault. 2 O otoA three-phase circuit is balanced. The source voltage for the a-phase has a magnitude of 100 volts, and you can assume the phase angle is a reference of 0 degrees. Write the phasor expressions with proper subscript notation for the source voltage for each leg of the three-phase source if it is in a positive phase sequence.
- Need asap pls help. Solve for the voltages across and currents through each component. Show the complete solution and explain. The total power should be zero..Consider the three single-phase two-winding transformers shown in Figure 3.37. The high-voltage windings are connected in Y. (a) For the low-voltage side, connect the windings in , place the polarity marks, and label the terminals a, b, and c in accordance with the American standard. (b) Relabel the terminals a, b, and c such that VAN is 90 out of phase with Va for positive sequence.A balanced Y-connected voltage source with Eag=2770volts is applied to a balanced-Y load in parallel with a balanced- load where ZY=20+j10andZ=30j15ohms. The Y load is solidly grounded. Using base values of Sbase1,=10kVAandVbaseLN=277volts, calculate the source current Ia in per-unit and in amperes