The average weight of 31 randomly selected minivans was 4150 pounds. The sample standard deviation was 480 pounds. Find the 99 percent confidence interval of the true population mean weight of minivans.

Q: In estimating the population mean with the population standard deviation unknown, if the sample size…

A: Given that, Population standard deviation is unknown and sample size (n) = 27

Q: A random group of 36 people in Toms River were asked “how much money did you spend at the grocery…

A: Given: Sample mean x¯=149.50 Sample size (n) = 36 Sample standard deviation (s) = 22.50 Confidence…

Q: If a 92% Confidence Interval for the Population Mean is (67.8, 78.9), find its Margin of Error.

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Q: For 30 randomly selected Rolling Stones concerts the mean gross earnings is 2.59 million dollars.…

A:

Q: You measure 41 watermelons' weights, and find they have a mean weight of 47 ounces. Assume the…

A: Given that: n= 41.0 , x̄= 47.0 s= 2.5 At 90.0 % confidence level , z score= 1.645 So, 90.0 %…

Q: A group of 49 randomly selected students has a mean age of 22.4 years with a standard  deviation of…

A: Sample mean = x̅ = 22.4 Sample size = n = 49 Sample S.D = s = 3.8 Standard Error = s/√n  =…

Q: The standard deviation of the weights of elephants is known to be approximately 15 pounds.  We wish…

A: Sample mean = x̅ = 244 Sample size = n = 50 Population S.D = σ = 15 Standard Error = σ/√n  =…

Q: In a random sample of six people, the mean driving distance to work was 24.9 miles and the standard…

A: The sample size: n=6 Sample mean: x¯=24.9 miles Standard deviation: s=7.9 Confidence level: C=0.99…

Q: In a random sample of eight ​people, the mean driving distance to work was 19.3 miles and the…

A: The question is about confidence interval Given : Randomly selected no. of people ( n ) = 8 Sample…

Q: A car repair business randomly selects receipts for parts purchased on 16 different jobs. The mean…

A: given data, n=16x¯=31.32s=30.42CI=0.95α=1-0.95=0.05df=n-1=16-1=15we  have to construct the 95%…

Q: Assume that the mean and standard deviation of a sample 10 units respectively. if the sample size is…

A: Sample size is n=25, sample standard deviation is 10 and mean is 10. The critical value is 2.0639…

Q: We take a sample of 50 people and obtain a sample mean of 147 pounds with a standard deviation of 15…

A: We have given that  Sample size n = 50 Sample mean = 147 Standard deviation = 15 90%confidence…

Q: According to the U.S. Bureau of Labor and Statistics, realtors in Michigan make $65,330 on average.…

A: Answer: From the given data, Sample size (n) = 30 Sample mean (x⏜) = $ 70125 Population standard…

Q: 4. A recent study of 19 students of San Rafael College showed that the mean of the distance they…

A:

Q: The population standard deviation for the height of college hockey players is 3.4 inches. If we want…

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Q: The average weight of 36 randomly selected school buses was 4150 pounds with a standard deviation of…

A: Given data,x=4150σ=480n=36z-value at 99% confidence is Zc=2.576

Q: A local police department made an effort to determine the average speed of automobiles travelling…

A:

Q: A random sample of 40 college students averaged 5 hours of sleep per night. Assume a population…

A: We have given that,  Sample size (n) = 40, sample mean or average (x̄) =5 and population standard…

Q: The mean for the verbal component of the SAT is reported as 500, with a standard deviation of 100. A…

A: It is given that the sample mean is 498 and the population standard deviation is 100.

Q: he average weight of 20 randomly selected cars was 3500 pounds. The sample standard deviation was…

A: given data, n=20df=n-1=20-1=19x¯=3500 pounds s=315 pounds CI=0.90α=1-0.90=0.10

Q: You collect a sample of 69 observations of animal heights, in mm. The sample mean is 41.89 and the…

A: Given: x¯=41.89s=4.33n=69 The degrees of freedom is obtained as below: df=n-1=69-1=68 The critical…

Q: A study was commissioned to find the mean weight of the residents in certain town. The study…

A: Given: n=58, x=174 and s=38. Now,Degrees of freedom=n-1=58-1=57 Then, at 95% confidence level, the…

Q: Find a 95% confidence interval for the proportion of renters.

A: It is given that  Favourable cases, X = 360 Sample size, n = 600 Confidence interval = 95%

Q: A random sample of 110 Americans was asked how many hot dogs they eat each year.  The sample mean…

A:

Q: For an SRS of 66 students, the average exam score was a 73. Assume you know the population standard…

A: Given,Standard deviation(σ)=10margin of error(E)=1.0α=1-0.99=0.01α2=0.005Z0.005=2.58     (from…

Q: 2. In a recent study of 35 college students, the mean number of hours per week that they played…

A: According to the given information in this question  We need to find the 95% confidence interval

Q: Suppose we are contracted by the Justice Department to study the extent of juvenile delinquency.  We…

A:

Q: A large urgent care center with 4 doctors found that they can see an average of 28 patients per…

A: We have given that Sample size (n) = 41Sample mean (x̅) = 28Standard deviations (s) =…

Q: survey asked 8 adults how many years of education they had. The sample mean was 12.90 with a sample…

A:

Q: The daily salaries of security guards for 10 security agencies are as follows: P350, P400, P375,…

A: Solution To find the point estimate we will find the sample mean.

Q: If the mean and standard deviation of a sample of size 45 is 1050 and 52 respectively, construct a…

A: It is given that Sample mean = 1050Sample standard deviation = 52Sample size = 45Confidence level =…

Q: A food snack manufacturer samples 9 bags of pretzels off the assembly line and weighs their…

A: Given information Sample size (n) = 9 Sample mean x̅ = 15.2 oz Standard deviation (s) = 0.50 oz…

Q: You measure 41 watermelons' weights, and find they have a mean weight of 79 ounces. Assume the…

A: Mean = 79Standard deviation = 2.4Sample size = 41

Q: An administrator in charge of undergraduate education on a large campus wanted to estimate the…

A: Introduction: The 100 (1 – α) % confidence interval for the population mean, μ, when the population…

Q: A researcher found that in a random sample of 50 retired men, the average number of jobs they had…

A: As per our guidelines we are suppose to answer three sub-parts. Given,Sample size(n)=50sample…

Q: A survey of first time homeowners found that the sample mean annual income was $53,000. Assume that…

A:

Q: The lead levels in a random sample of 35 crows in the region were measured and recorded. The mean…

A: It is given that  Sample size n = 35 Sample mean M = 4.50 Sample SD s = 1.12 Confidence level = 99%…

Q: From a random sample of 36 months from January 2006 through December 2020, the mean number of…

A: The given values are:Sample size (n) = 36Sample mean (x̄) = 94Population standard deviation (σ) =…