The average time it takes for a molecule to diffuse a distance of x cm is given by t = 2D Assume that the diffusion coefficient of glucose is 5.70 x 10 Round your answer to 3 significant digits. Diffusion time (t) = X -7 cm S 2 where t is the time in seconds and D is the diffusion coefficient. Calculate the time it would take for a glucose molecule to diffuse 18.5 µm.

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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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**Diffusion Time Calculation**

The average time it takes for a molecule to diffuse a distance of \( x \) cm is given by the equation:

\[ t = \frac{x^2}{2D} \]

where:
- \( t \) is the time in seconds.
- \( D \) is the diffusion coefficient.

Assume the diffusion coefficient of glucose is \( 5.70 \times 10^{-7} \, \text{cm}^2/\text{s} \).

**Task:**
Calculate the time it would take for a glucose molecule to diffuse 18.5 µm.

*Instructions:*
- Round your answer to 3 significant digits.

**Input Section:**
- **Diffusion time (\( t \)) =** \(\boxed{\phantom{0}}\) s

*Options:*
- Save for Later
- Submit

**Note:**
Ensure that the distance is converted to the correct unit (cm) before substituting into the formula.
Transcribed Image Text:**Diffusion Time Calculation** The average time it takes for a molecule to diffuse a distance of \( x \) cm is given by the equation: \[ t = \frac{x^2}{2D} \] where: - \( t \) is the time in seconds. - \( D \) is the diffusion coefficient. Assume the diffusion coefficient of glucose is \( 5.70 \times 10^{-7} \, \text{cm}^2/\text{s} \). **Task:** Calculate the time it would take for a glucose molecule to diffuse 18.5 µm. *Instructions:* - Round your answer to 3 significant digits. **Input Section:** - **Diffusion time (\( t \)) =** \(\boxed{\phantom{0}}\) s *Options:* - Save for Later - Submit **Note:** Ensure that the distance is converted to the correct unit (cm) before substituting into the formula.
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