The average person passes out at an acceleration of 7g (that is, seven times the gravitational acceleration on Earth). Suppose a car is designed to accelerate at this rate. How much time would be required for the car to accelerate from rest to 66.2 miles per hour? (The car would need rocket boosters!) Answer is in seconds!

The average person passes out at an acceleration of 7g (that is, seven times the gravitational acceleration on Earth). Suppose a car is designed to accelerate at this rate. How much time (in seconds) would be required for the car to accelerate from rest to 59.9 miles per hour? (The car would need rocket boosters!)

Julie drives 112 mi to Grandmother's house. On the way to Grandmother's house, Julie drives half the distance at 41 mph and half the distance at 60 mph. On her return trip, she drives half the time at 41 mph and half the time at 60 mph. What is her average speed on the return trip?

The van travels over the hill described by y=(-1.5x10 ')x²+15) ft. If it has a constant speed of 71 ft/s, determine the x component of the van's velocity when x = 50 ft. y= (-1,5(10- + 15) ft 15 ft 100 t

Without turning around, a dog walks along a long straight path for 4.0 m at 3.0 m/s and then for 2.0 s at 6.0 m/s. What was the average speed of the dog?

Fast Car: On a hot day in the flats, the temperature is 103.6 degrees. A driver finds an empty, flat stretch of desert that is 1776 meters long and decides to push the limits of his car. He finds the car can accelerate from 0 to 60 mph (26.8 m/s) in 4.30 s. Now he wants to see how fast the car can go. Assume the car maintains the same average acceleration until it reaches its top speed of 84.8 m/s. (a) How long will it take the car to reach its top speed? (b) How far will the car travel before it reaches its top speed?

A ball is thrown straight up in the air with an initial speed of 10 m/s. Ignore air resistance and take g = 10m/s2. What is the speed of the ball when it reach 5 m above the ground? O m/s 5 m/s 5/2 m/s 10 m/s 10/2 m/s

There is a 1500 mile race course. The max forward acceleration is 4 m/s2 and the max backward acceleration is 6 m/s2. I start at 600 m and must go to the 800 m mark (I must travel 200 m). What is an equation for the fastest time that I could get to 800 m? What is the position, time, and velocity of my vehicle?

You are to drive to an interview in another town, at a distance of 300km. You leave for the interview 3 ¼ hours before it is scheduled, planning to drive at 100 km/hr. You drive at that speed for the first 100 km. Then, construction work on the road causes you to drive at 40 km/hr for 60 km. At what constant speed must you drive the rest of the way to get to the interview on time.

We are given the following data about the speed of a vehicle with time: 0 Time (1) Speed (v) 5.2 5 4.8 10 8.3 15 6.0 Compute the value of acceleration (rate of change of velocity) at time t=10 using the forward-difference method. Report your answer correctly to two decimal places (with an appropriate + or - sign).