The average expenditure on Valentine's Day was expected to be $100.89. The average expenditure in a sample survey of 40 male consumers was $138.29 and the average expenditure in a sample survey of 30 female consumers was $61.66. Based on past surveys, the standard deviation for male consumers is assumed to be $32, and the standard deviation for female consumers is assumed to be $14. The z value is 2.576. At 99% confidence, what is the margin of effort?

Use z scores to compare the given values. In a recent awards ceremony, the age of the winner for best actor was 33 and the age of the winner for best actress was 47. For all best actors, the mean age is 44.4 years and the standard deviation is 6.5 years. For all best actresses, the mean age is 32.8 years and the standard deviation is 11.2 years. (All ages are determined at the time of the awards ceremony.) Relative to their genders, who had the more extreme age when winning the award, the actor or the actress? Explain. Since the z score for the actor is z= and the z score for the actress is z = the V had the more extreme age. (Round to two decimal places.)

Suppose that the cost of annual tuition at colleges is normally distributed, with an average annual cost of $13,926.78. The standard deviation of tuition is $4,085.42. What proportion of colleges would be expected to have an annual tuition between the cost of College A with a tuition of $20,106.18 and College B with a tuition of $14,829.01?

The average McDonald's restaurant generates $3.6 million in sales each year with a standard deviation of 0.9. Trent wants to know if the average sales generated by McDonald's restaurants in Kentucky is different than the worldwide average. He surveys 27 restaurants in Kentucky and finds the following data (in millions of dollars): 4.1, 2.8, 4.4, 4.5, 5.3, 5, 3.7, 2.9, 3.8, 4.8, 3.6, 2.3, 3.7, 2.9, 2.9, 4, 1.1, 5.2, 2.9, 5, 4, 4, 5.9, 3.2, 2.2, 4.3, 3.8 Perform a hypothesis test using a 3% level of significance. Step 1: State the null and alternative hypotheses. Ho: [? v] ? v На: ? ? v (So we will be performing a Select an answer test.) Step 2: Assuming the null hypothesis is true, determine the features of the distribution of point estimates using the Central Limit Theorem. By the Central Limit Theorem, we know that the point estimates are Select an answer v with distribution mean and distribution standard deviation Step 3: Find the p-value of the point estimate. P( ? v ? v = P( ? ♥ ?…